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PilotLPTM [1.2K]
3 years ago
13

.

Mathematics
2 answers:
Gnesinka [82]3 years ago
6 0

Answer:

7%

Step-by-step explanation:

The number of degrees in a circle is 360°

The percentage of a particular angle can be calculated as

\frac{angle}{360} × 100%

Thus for an angle of 25°

percent = \frac{25}{360} × 100% = \frac{25(100)}{360} ≈ 7% ( to the nearest whole number )

Allisa [31]3 years ago
4 0

Answer:

7%

Step-by-step explanation:

25/360 × 100 = 6.944

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(question is on picture linked)
nalin [4]

here y+13=15

so we got y=2

then y+13+x+12=30

then we will get x=3

7 0
3 years ago
I Need Help Fast Please
lbvjy [14]
C. 130,90,130.

#01234, the tenths number stays the same
#56789, the tenths number go up 1 number

4 0
3 years ago
A sample of 140 Vopstra customers have had their annual phone charge recorded for the previous calendar year. The data were used
taurus [48]

Answer:

Correct option: (a)

Step-by-step explanation:

A confidence interval is an interval estimate of the parameter value.

A (1 - <em>α</em>)% confidence interval implies that the confidence interval has a (1 - <em>α</em>)% probability of consisting the true parameter value.

OR

If 100 such confidence intervals are made then (1 - <em>α</em>) of these intervals would consist the true parameter value.

The 92% confidence interval for the mean annual phone charge of all Vopstra customers is:

\$470\pm \$65=(\$405, \$535)

This confidence interval implies that true mean annual phone charge of all Vopstra customers is contained in the interval ($405, $535) with 0.92 probability.

Thus, the correct option is (a).

6 0
4 years ago
If 84 cookies will serve 24 students, how many cookies are needed for 30 students ?
allsm [11]
105 cookies
84 \div 24 = 3.5
3.5 \times 30 = 105
6 0
3 years ago
Read 2 more answers
How to factor 6n2 - 6n - 12
alexandr402 [8]

We see that in these 3 terms, 6 is a common factor. So, let's factor out a 6:

6n^2-6n-12 = 6(n^2-n-2)

We can set this equal to 0 and factor by using the quadratic formula which is:

x = \frac{-b \pm \sqrt{b^2-4ac} }{2a}

So, let's do just that:

6(n^2-n-2) = 0

Note that the 6 goes away if you divide both sides by 6. In this case, a = 1, b = -1, and c = -2. Let's plug that into the quadratic equation:

\frac{1 \pm \sqrt{(-1)^2-4(1)(-2)} }{2(1)} = \frac{-1 \pm \sqrt{1-(-8)} }{2}

\frac{-1 \pm \sqrt{9} }{2} = {1, -2}

So, we can write this as:

6n^2 - 6n - 12 = 6(n-1)(n+2)

Notice that the 6 comes back because it was only temporarily mad. And that the roots have opposite signs in the parentheses because to find the roots, you need to set each parentheses equal to 0 and solve for n. With that in mind, your final answer is 6(n-1)(n+2). Hope I could help you!

7 0
3 years ago
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