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zaharov [31]
11 months ago
6

suppose that two players are playing the following game. player 1 can choose either top or bottom, and player 2 can choose eithe

r left or right. the payoffs are given in the following table: where the number on the left is the payoff to player a, and the number on the right is the payoff to player b. if each player plays their maximin strategy, the outcome of the game will be player b player a left right top 8 1 2 6 bottom 3 5 4 2 group of answer choices top/left top/right bottom/left bottom/right
Mathematics
1 answer:
alisha [4.7K]11 months ago
8 0

A) Player 1 does not have a dominant strategy because if player 2 plays left, then player 1 should play bottom but if player 2 plays right then player 1 should play top. For a dominant strategy to existing player 1 would have to chose top or bottom regardless of what player 2 does.

B) Player 2 has a dominant strategy of left because this always produces a better outcome for this player. Specifically, if player 1 plays top player 2 is better off playing left (since 5 > 4) and if player 1 plays bottom player 2 is still better off playing left (since 4 > 3)

C) i) Top/Left is not a Nash Equilibrium because if player 2 plays left then player 1 would be better off playing bottom and it only takes one player wanting to deviate to ruin a potential Nash Equilibrium.

Simplest 3 varieties of stresses can exchange the composition of an equilibrium aggregate: (1) a change inside the concentrations (or partial pressures) of the additives by using adding or doing away with reactants or merchandise, (2) an alternate in the general strain or quantity, and (three) an exchange within the temperature of the gadget.

To learn more about A) Player 1 does not have a dominant strategy because if player 2 plays left, then player 1 should play bottom but if player 2 plays right then player 1 should play top. For a dominant strategy to existing player 1 would have to chose top or bottom regardless of what player 2 does.

B) Player 2 has a dominant strategy of left because this always produces a better outcome for this player. Specifically, if player 1 plays top player 2 is better off playing left (since 5 > 4) and if player 1 plays bottom player 2 is still better off playing left (since 4 > 3)

C) i) Top/Left is not a Nash Equilibrium because if player 2 plays left then player 1 would be better off playing bottom and it only takes one player wanting to deviate to ruin a potential Nash Equilibrium.

Simplest 3 varieties of stresses can exchange the composition of an equilibrium aggregate: (1) a change inside the concentrations (or partial pressures) of the additives by using adding or doing away with reactants or merchandise, (2) an alternate in the general strain or quantity, and (three) an exchange within the temperature of the gadget.

To learn more about Equilibrium visit:brainly.com/question/13463225

#SPJ4

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Leokris [45]

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5 0
3 years ago
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disa [49]

Answer:

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Step-by-step explanation:

6 0
2 years ago
The volume of the plastic cylinder is 64. A glass cylinder has the same height and radius is half of the plastic cylinder radius
sp2606 [1]

Answer:

I am not sure if I'm correct, but I got 16

Step-by-step explanation:

lets look at the formula for cylinder volume:

V=π*r^(2)*h

now, lets plug in 64

64=π*r^(2)*h

h=64/(π*r^(2))

Volume of glass cylinder is

V=((0.5r)^2)*(64/(π*r^(2)))*π

V=0.25π*r^(2)*(64/(π*r^(2)))

V=16π*r^(2)/(π*r^(2)

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8 0
3 years ago
The graph of the piecewise function f(x) is shown.
NeTakaya

Answer:

{f(x) | -∞ < f(x) ≤ 4 }

Step-by-step explanation:

The range is made up of the y values.  Remember f(x) = y

In this graph the least value of y is -∞ and the greatest value of y is 4

So, the range is {f(x) | -∞ < f(x) ≤ 4 } which is the 2nd choice

4 0
2 years ago
Find the 12th term in the following arithmetic sequence
sattari [20]
It is going up by 5 so i believe your answer would be 57
4 0
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