Answer:
Bruce's function:
![\displaystyle y=\frac{1}{4}x](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y%3D%5Cfrac%7B1%7D%7B4%7Dx)
Felicia's function:
![\displaystyle y=\frac{1}{9}x](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y%3D%5Cfrac%7B1%7D%7B9%7Dx)
<em>Bruce's tiles cover more area</em>
Step-by-step explanation:
<u>Functions
</u>
We need to compare the area covered by tile of both Bruce and Felicia. We are required to find the function y, the area covered by the number of tiles he used, x.
We know the tiles used by Bruce cover 1/4 of a square foot, this is written as:
![\displaystyle y=\frac{1}{4}x](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y%3D%5Cfrac%7B1%7D%7B4%7Dx)
To find the function for Felicia, we must use the data provided in the table
For example,
For x=9 tiles, y=1 sq ft
For x=18 tiles, y=2 sq ft
If we set
![\displaystyle y=kx](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y%3Dkx)
We can find the value of k
![\displaystyle 1=9k](https://tex.z-dn.net/?f=%5Cdisplaystyle%201%3D9k)
![\displaystyle k=\frac{1}{9}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20k%3D%5Cfrac%7B1%7D%7B9%7D)
Thus
![\displaystyle y=\frac{1}{9}x](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y%3D%5Cfrac%7B1%7D%7B9%7Dx)
Testing the constructed function with x=18 and x=27
![\displaystyle y=\frac{1}{9}18=2](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y%3D%5Cfrac%7B1%7D%7B9%7D18%3D2)
![\displaystyle y=\frac{1}{9}27=3](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y%3D%5Cfrac%7B1%7D%7B9%7D27%3D3)
The function is complete and accurate.
Comparing both functions we see that Bruce's tiles cover more area because
![\displaystyle \frac{1}{4}>\frac{1}{9}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B1%7D%7B4%7D%3E%5Cfrac%7B1%7D%7B9%7D)
Answer:
8
Step-by-step explanation:
i used the calculator
We have diameter=18 inches
so diameter= 2* radius
radius=18/2= 9
r=9
Area of a circle =
![\pi \times r^{2}](https://tex.z-dn.net/?f=%5Cpi%20%5Ctimes%20r%5E%7B2%7D%20)
so Area=
![\pi \times {9}^{2} \\ 81 \times \pi \\](https://tex.z-dn.net/?f=%5Cpi%20%5Ctimes%20%7B9%7D%5E%7B2%7D%20%5C%5C%2081%20%5Ctimes%20%5Cpi%20%5C%5C%20)
Since we take pi as 3.14 we get area as= 81*3.14
Area= 254.34
rounding up to the nearest tenth
![ans = 254.3 \: in^{2}](https://tex.z-dn.net/?f=ans%20%3D%20254.3%20%5C%3A%20in%5E%7B2%7D%20)
Second answer
8.544 is the sqare root with a remainder
Answer: no
Step-by-step explanation: no