WHAT IS 11/6 simplified I CANT DO THIS MATH IT IS TOOOOO HARDDDDD JK IM JUST TO LAZY >:( thanks

A garden is shaped in the form of a regular heptagon (seven-sided), MNSRQPO. A circle with center T and radius 25m circumscribes

Alenkinab [10]

The relationship between the sides MN, MS, and MQ in the given regular heptagon is $\dfrac{1}{MN} = \dfrac{1}{MS} + \dfrac{1}{MQ}$

The area to be planted with flowers is approximately 923.558 m²

The reason the above value is correct is as follows;

The known parameters of the garden are;

The radius of the circle that circumscribes the heptagon, r = 25 m

The area left for the children playground = ΔMSQ

Required;

The area of the garden planted with flowers

Solution:

The area of an heptagon, is;

$A = \dfrac{7}{4} \cdot a^2 \cdot cot \left (\dfrac{180 ^{\circ}}{7} \right )$

The interior angle of an heptagon = 128.571°

The length of a side, S, is given as follows;

$\dfrac{s}{sin(180 - 128.571)} = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)}$

$s = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)} \times sin(180 - 128.571) \approx 21.69$

$The \ apothem \ a = 25 \times sin \left ( \dfrac{128.571}{2} \right) \approx 22.52$

The area of the heptagon MNSRQPO is therefore;

$A = \dfrac{7}{4} \times 22.52^2 \times cot \left (\dfrac{180 ^{\circ}}{7} \right ) \approx 1,842.94$

$MS = \sqrt{(21.69^2 + 21.69^2 - 2 \times 21.69 \times21.69\times cos(128.571^{\circ})) \approx 43.08$

By sine rule, we have

$\dfrac{21.69}{sin(\angle NSM)} = \dfrac{43.08}{sin(128.571 ^{\circ})}$

$sin(\angle NSM) =\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ})$

$\angle NSM = arcsin \left(\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ}) \right) \approx 23.18^{\circ}$

∠MSQ = 128.571 - 2*23.18 = 82.211

The area of triangle, MSQ, is given as follows;

$Area \ of \Delta MSQ = \dfrac{1}{2} \times 43.08^2 \times sin(82.211^{\circ}) \approx 919.382^{\circ}$

The area of the of the garden plated with flowers, $A_{req}$ , is given as follows;

$A_{req}$ = Area of heptagon MNSRQPO - Area of triangle ΔMSQ

Therefore;

$A_{req}$ = 1,842.94 - 919.382 ≈ 923.558

The area of the of the garden plated with flowers, $A_{req}$ ≈ 923.558 m²

Learn more about figures circumscribed by a circle here:

brainly.com/question/16478185

6 0

3 years ago

Please answer correctly !!!! Will mark brainliest !!!!!!!!!

Burka [1]

Answer:

Area = l x w

Area = (x + 1)(x + 7)

Area = x² + 7x + x + 7

Area = x² + 8x + 7

Step-by-step explanation:

8 0

3 years ago

Help, please (single variable calculus)

balandron [24]

Hi there!

$\large\boxed{ 14.875}$

Our interval is from 0 to 3, with 6 intervals. Thus:

3 ÷ 6 = 0.5, which is our width for each rectangle.

Since n = 6 and we are doing a right-riemann sum, the points we will be plugging in are:

0.5, 1, 1.5, 2, 2.5, 3

Evaluate:

(0.5 · f(0.5)) + (0.5 · f(1)) + (0.5 · f(1.5)) + (0.5 · f(2)) + (0.5 · f(2.5)) + (0.5 · f(3)) =

Simplify:

0.5( -2.75 + (-3) + (-.75) + 4 + 11.25 + 21) = 14.875

7 0

3 years ago

2 For each figure, are 21 and 22 adjacent angles or vertical angles? Explain. b. a. 2

kupik [55]

Answer:

a is vertical and b is adjacent angles

3 0

3 years ago

Set points graph math question pic included

Gnom [1K]

Answer:

(-5,2) and (5,2)

Hoped this helped, have a nice day!

7 0

3 years ago