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konstantin123 [22]
3 years ago
11

If you loan $500 to a friend for 6 months and charge $50 total

Mathematics
1 answer:
oee [108]3 years ago
6 0

Step-by-step explanation:

S=(P×R×T)÷100

R=(100×S)÷P×T, given that S= simple interest, P=principal amount,T=time and R=rate.

R=(100×50)÷500×6

R=1.67

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PLZ HELP!!! Which of the following does not represent a function?
alex41 [277]
It should be the 3rd one
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E.g. y = a (correct)
y = +/-a (incorrect)
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3 years ago
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2 divided by what equals 20
Tpy6a [65]

Answer:

40

Step-by-step explanation:

40 divided by 2 = 20

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What is the y-intercept of the line represented by y = 4x?
alexandr402 [8]
0, there is no y-intecept.
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Looking at the top of tower A and base of tower B from points C and D, we find that ∠ACD = 60°, ∠ADC = 75° and ∠ADB = 30°. Let t
katrin2010 [14]

Answer:

\text{Exact: }AB=25\sqrt{6},\\\text{Rounded: }AB\approx 61.24

Step-by-step explanation:

We can use the Law of Sines to find segment AD, which happens to be a leg of \triangle ACD and the hypotenuse of \triangle ADB.

The Law of Sines states that the ratio of any angle of a triangle and its opposite side is maintained through the triangle:

\frac{a}{\sin \alpha}=\frac{b}{\sin \beta}=\frac{c}{\sin \gamma}

Since we're given the length of CD, we want to find the measure of the angle opposite to CD, which is \angle CAD. The sum of the interior angles in a triangle is equal to 180 degrees. Thus, we have:

\angle CAD+\angle ACD+\angle CDA=180^{\circ},\\\angle CAD+60^{\circ}+75^{\circ}=180^{\circ},\\\angle CAD=180^{\circ}-75^{\circ}-60^{\circ},\\\angle CAD=45^{\circ}

Now use this value in the Law of Sines to find AD:

\frac{AD}{\sin 60^{\circ}}=\frac{100}{\sin 45^{\circ}},\\\\AD=\sin 60^{\circ}\cdot \frac{100}{\sin 45^{\circ}}

Recall that \sin 45^{\circ}=\frac{\sqrt{2}}{2} and \sin 60^{\circ}=\frac{\sqrt{3}}{2}:

AD=\frac{\frac{\sqrt{3}}{2}\cdot 100}{\frac{\sqrt{2}}{2}},\\\\AD=\frac{50\sqrt{3}}{\frac{\sqrt{2}}{2}},\\\\AD=50\sqrt{3}\cdot \frac{2}{\sqrt{2}},\\\\AD=\frac{100\sqrt{3}}{\sqrt{2}}\cdot\frac{ \sqrt{2}}{\sqrt{2}}=\frac{100\sqrt{6}}{2}={50\sqrt{6}}

Now that we have the length of AD, we can find the length of AB. The right triangle \triangle ADB is a 30-60-90 triangle. In all 30-60-90 triangles, the side lengths are in the ratio x:x\sqrt{3}:2x, where x is the side opposite to the 30 degree angle and 2x is the length of the hypotenuse.

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3 0
3 years ago
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Which of the following vectors are orthogonal to (1,5)? Check all that apply
Andre45 [30]
We know that
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</span><span>B. (10,-2)
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<span>C. (-1,-5)
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<span>D. (-5,1)
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the answer is 
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7 0
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