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3 years ago

I need FAST help???????????

Mathematics

2 answers:

EleoNora [17]3 years ago

5 0

Here what do we observe:-

Two opposite side pairs are parallel so they are surely equal.(Generic Quadrilateral rejected)
Two opposite angle pairs are equal (Rhombus and rectangle omitted)

Hence it's a PARALLELOGRAM.

lidiya [134]3 years ago

5 0

Answer:

Parallelogram

Step-by-step explanation:

The pictured quadrilateral is not:

A rectangle - as we don't see right angles
A rhombus - as we don't see 4 equal sides
A generic quadrilateral - as it has parallel sides and equal angles

This is:

A parallelogram - as it has two pairs of parallel sides and two pairs of equal opposite angles.

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Alicia has 7 paintings she wants to hang side by side on her wall.

melisa1 [442]

The question is an illustration of permutation and combinations.

The number of ways she can choose 4 out of the 7 paintings is 35
The number of ways she can arrange 4 out of the 7 paintings is 840

The given parameters are:

$\mathbf{n = 7}$

$\mathbf{r = 4}$

(a) Choose 4 of 7 paintings

Choosing 4 of 7 paintings implies combination.

So, we have:

$\mathbf{^nC_r = \frac{n!}{(n - r)!r!}}$

Substitute values for n and r

$\mathbf{^7C_4 = \frac{7!}{(7 - 4)!4!}}$

$\mathbf{^7C_4 = \frac{7!}{3!4!}}$

Expand

$\mathbf{^7C_4 = \frac{7 \times 6 \times 5 \times 4!}{3 \times 2 \times 1 \times 4 !}}$

$\mathbf{^7C_4 = 35}$

Hence, the number of ways she can choose 4 out of the 7 paintings is 35

(b) Arrange 4 of 7 paintings

Arranging 4 of 7 paintings implies permutation.

So, we have:

$\mathbf{^nP_r = \frac{n!}{(n - r)!}}$

Substitute values for n and r

$\mathbf{^7P_4 = \frac{7!}{(7 - 4)!}}$

$\mathbf{^7P_4 = \frac{7!}{3!}}$

Expand

$\mathbf{^7P_4 = \frac{7 \times 6 \times 5 \times 4 \times 3!}{3!}}$

$\mathbf{^7P_4 = 840}$

Hence, the number of ways she can arrange 4 out of the 7 paintings is 840

Read more about permutation and combinations at:

brainly.com/question/15301090

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Step-by-step explanation:

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