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Bogdan [553]
3 years ago
5

The slope of (3,6) and (5,2)

Mathematics
1 answer:
Elden [556K]3 years ago
3 0

\text{Hey there!}

\mathsf{The\ slope\ formula\ is: \dfrac{y_2-y_1}{x_2-x_1}}

\mathsf{y_2=2}\\\mathsf{y_1=6}

\mathsf{x_2=5}\\\mathsf{x_1=3}

\mathsf{Equation: \dfrac{2-6}{5-3}}\\\\\bullet\mathsf{2-6=-4\leftarrow your\ \bf{y}\mathsf{\ value}}\\\\\bullet{\mathsf{5-3=2\leftarrow your\  \bf{x}\ \mathsf{value}}}\\\\\mathsf{New\ equation/answer:\ \dfrac{-4}{2}}\\\\\boxed{\bf{Answer:\mathsf{-2\ or\ \dfrac{-4}{2}}}}

\text{Good luck on your assignment enjoy your day!}

~\frak{LoveYourselfFirst:)}

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Find the greatest number that divides451, 328 and 673 leaving 1, 4 and 1,respectively as remainders.
Vesna [10]

You're looking for the largest number <em>x</em> such that

<em>x</em> ≡ 1 (mod 451)

<em>x</em> ≡ 4 (mod 328)

<em>x</em> ≡ 1 (mod 673)

Recall that

<em>x</em> ≡ <em>a</em> (mod <em>m</em>)

<em>x</em> ≡ <em>b</em> (mod <em>n</em>)

is solvable only when <em>a</em> ≡ <em>b</em> (mod gcd(<em>m</em>, <em>n</em>)). But this is not the case here; with <em>m</em> = 451 and <em>n</em> = 328, we have gcd(<em>m</em>, <em>n</em>) = 41, and clearly

1 ≡ 4 (mod 41)

is not true.

So there is no such number.

4 0
3 years ago
Find the m∠DCA A. 10 B. 29 C. 116 D. 40
Blizzard [7]
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5 0
3 years ago
Help plz I wanna be done with homework for the day :(
Studentka2010 [4]

Answer:

ohhhh we have the same question

Step-by-step explanation:

6 0
3 years ago
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Graph this rational equation. Identify the points of discontinuity, holes, vertical asymptotes, x-intercepts, and horizontal asy
irakobra [83]

Step-by-step explanation:

We have given,

A rational function : f(x) = \frac{x-2}{x-4}

W need to find :

Point of discontinuity : - At x = 4, f(x) tends to reach infinity, So we get discontinuity point at x =4.

For no values of x, we get indetermined form (i.e \frac{0}{0}), Hence there is no holes

Vertical Asymptotes:

Plug y=f(x) = ∞ in f(x) to get vertical asymptote   {We can us writing ∞ = \frac{1}{0}}

i.e ∞ = \frac{x-2}{x-4}

or \frac{1}{0}=\frac{x-2}{x-4}

or x-4 =0

or x=4, Hence at x = 4, f(x) has a vertical asymptote

X -intercept :

Plug f(x)=0 , to get x intercept.

i.e 0 = \frac{x-2}{x-4}

or x - 2 =0

or x = 2

Hence at x=2, f(x) has an x intercept

Horizontal asymptote:

Plug x = ∞ in f(x) to get horizontal asymptote.

i.e f(x) = \frac{x-2}{x-4} = \frac{x(1-\frac{2}{x} )}{x(1-\frac{4}{x} )}

or f(x) = \frac{(1-\frac{2}{∞} )}{(1-\frac{4}{∞} )}

or f(x) = 1 = y

hence at y =f(x) = 1, we get horizontal asymptote





4 0
3 years ago
What is the GCF of 35 and 42
zzz [600]
The greatest common factor of 35 and 42 is 7

35/7 is 5 and 42/7 is 6

Hope this helps!
3 0
3 years ago
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