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3 years ago

14

I am a prime number greater than 40 and less than 90. My units digit and my tens digit are both prime. The difference between my

units digit and tens digit is not 2. What number am i?

1 answer:

Cloud [144]3 years ago

3 0

I think it could be 73. Because if you check what it the question says 73 fits them.

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Work out the value of: (√3)^2

Viktor [21]

Answer:

3

Step-by-step explanation:

Note that

( $\sqrt{a}$ )² = a, for example

( $\sqrt{100}$ )² = 10² = 100 ← value inside the radical

Thus

( $\sqrt{3}$ )² = 3

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3 years ago

Start by writing and solving an

djverab [1.8K]

k: the number of Kurds

t: the number of Turks

k=k

t=4k

k+t=66,000,000

k+4k=66,000,000

5k=66,000,000

k=13,200,000

t=52,800,000

Step-by-step explanation:

plz brain list.

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3 years ago

Find the cardinal number of the given set.<br><br><br> A = {{3, 5, 7, ... 25}}

Allisa [31]

Answer:

<h3>12</h3>

Step-by-step explanation:

The cardinal number of a set is the number of element in the set. Given the set A = {{3, 5, 7, ... 25}}, you can see that the elements of the set are odd numbers from 3 to 25. Writing out the full set;

A = {{3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25}}

Counting the total number of element in the set, you will see that there are only 12 elements in the set. Hence the cardinal number of the set is 12 i.e n(A) = 12

7 0

2 years ago

An important problem encountered by personnel directors and others faced with the selection of the best in a finite set of eleme

SVETLANKA909090 [29]

Answer:

1.63% probability that the 10 selected include include all the best 5 engineers in the group of 20

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the engineers are selected is not important, so the combinations formula is used to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Desired outcomes:

10 engineers selected from a set of 20.

5 best, from a set of 5.

Other 5, from a set of 20-5 = 15.

$D = C_{5,5}*C_{15,5} = \frac{5!}{5!(5-5)!}*\frac{15!}{5!(15-5)!} = 3003$

Totao outcomes:

10 engineers selected from a set of 20.

$T = C_{20,10} = \frac{20!}{10!(20-10)!} = 184756$

Probability:

$p = \frac{D}{T} = \frac{3003}{184756} = 0.0163$

1.63% probability that the 10 selected include include all the best 5 engineers in the group of 20

5 0

3 years ago

Least common denominator of 1/8 2/9 and 3/12

Readme [11.4K]

Answer:

least common denominator is 72

8 goes into 72 9 times

9 goes into 72 8 times

12 goes into 72 6 times

Step-by-step explanation:

6 0

3 years ago