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irina [24]
3 years ago
9

In 2016 the United States had a population of about 323 million people and was growing at 0.7 %. Use an explicit exponential mod

el to predict what year the U.S. population will reach 400 million people
Mathematics
1 answer:
ElenaW [278]3 years ago
5 0

Answer:

2047

Step-by-step explanation:

We are given that

Growing rate=0.7%

\frac{dp}{dt}=\frac{0.7}{100}P

\int \frac{dP}{P}=0.007\int dt

lnP=0.007t+C

Using the formula

\int \frac{dx}{x}=ln x+C

P=e^{0.007t+C}=e^{0.007t}\cdot e^C=Ae^{0.007t}

e^C=A

Initially when t=0,P=323 million

Substitute the values

323 million=A

P=323e^{0.007t}

Now, substitute P=400 million

400=323e^{0.007t}

ln\frac{400}{323}=0.007t

ln(1.2384)=0.007t

t=\frac{ln(1.2384}{0.007}

t=30.5\approx 31 Years

Year=2016+31=2047

Hence,In 2047 the U.S population will reach 400 million people.

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Step-by-step explanation:

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(solve for x):

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6(20)-25 = 120-25 = 95

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Answer:

Step-by-step explanation:

The formula for determining the confidence interval for the difference of two population means is expressed as

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Where

x1 = mean sale amount for mail order sales = 82.70

x2 = mean sale amount for internet sales = 66.9

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n2 = number of internet sales = 10

For a 99% confidence interval, we would determine the z score from the t distribution table because the number of samples are small

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Margin of error =

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The delivery times for all food orders at a fast-food restaurant during the lunch hour are normally distributed with a mean of m
UkoKoshka [18]

Answer:

Let X the random variable that represent the delivery times of a population, and for this case we know the distribution for X is given by:

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Where \mu=14.7 and \sigma=3.7

Since the distribution of X is normal then we know that the distribution for the sample mean \bar X is given by:

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And we have;

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Step-by-step explanation:

Assuming this question: The delivery times for all food orders at a fast-food restaurant during the lunch hour are normally distributed with a mean of 14.7 minutes and a standard deviation of 3.7 minutes. Let R be the mean delivery time for a random sample of 40 orders at this restaurant. Calculate the mean and standard deviation of \bar X Round your answers to two decimal places.

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the delivery times of a population, and for this case we know the distribution for X is given by:

X \sim N(14.7,3.7)  

Where \mu=14.7 and \sigma=3.7

Since the distribution of X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we have;

\mu_{\bar X}= 14.70

\sigma_{\bar X} =\frac{3.7}{\sqrt{40}}= 0.59

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Answer:

The matrix is not invertible.

Step-by-step explanation:

We are given the following matrix in the question:

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Condition for invertible matrix:

A matrix is invertible if and only if the the determinant is non-zero.

We can find the determinant of the matrix as:

|A| = -5[(3)(6)-(2)(10)]-0[(-1)(6)-(2)(0)] + 1[(-1)(10)-(3)(0)]\\|A| = -5(18-20)+(-10)\\|A| = 10-10\\|A| = 0

Since the determinant of the given matrix is zero, the given matrix is not invertible.

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3 years ago
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