All categories

3 years ago

Please help! Will give branliest for correct answer ! God Bless uu!!

Mathematics

2 answers:

mafiozo [28]3 years ago

8 0

Answer:

Solution given:.

area of traingle EFG=1/2b×h=1/2×7×6=21cm²

area of rectangle ABCD=l×b=(20+9)×7=203cm²

area of rectangle BHIJ=l×b=9×11=99cm²

Total area =21+203+99=323cm² is a required answer

katen-ka-za [31]3 years ago

5 0

323 cm squared is the answer

Top rectangle: 9x18= 162
Lower rectangle: 20x7=140
Triangle: 1/2bh = 1/2(6)(7) = 21

162+140+21 = 323 cm squared

You might be interested in

Help 69 points

worty [1.4K]

Answer:

a) No Solution

Step-by-step explanation:

36 - 7p = -7(p - 5)

36 - 7p = -7p + 35

1 - 7p = -7p

1 = 0p

so a) No Solution

8 0

2 years ago

Prove or disprove (from i=0 to n) sum([2i]^4) <= (4n)^4. If true use induction, else give the smallest value of n that it doe

ddd [48]

Answer:

The statement is true for every n between 0 and 77 and it is false for $n\geq 78$

Step-by-step explanation:

First, observe that, for n=0 and n=1 the statement is true:

For n=0: $\sum^{n}_{i=0} (2i)^4=0 \leq 0=(4n)^4$

For n=1: $\sum^{n}_{i=0} (2i)^4=16 \leq 256=(4n)^4$

From this point we will assume that $n\geq 2$

As we can see, $\sum^{n}_{i=0} (2i)^4=\sum^{n}_{i=0} 16i^4=16\sum^{n}_{i=0} i^4$ and $(4n)^4=256n^4$ . Then,

$\sum^{n}_{i=0} (2i)^4 \leq(4n)^4 \iff \sum^{n}_{i=0} i^4 \leq 16n^4$

Now, we will use the formula for the sum of the first 4th powers:

$\sum^{n}_{i=0} i^4=\frac{n^5}{5} +\frac{n^4}{2} +\frac{n^3}{3}-\frac{n}{30}=\frac{6n^5+15n^4+10n^3-n}{30}$

Therefore:

$\sum^{n}_{i=0} i^4 \leq 16n^4 \iff \frac{6n^5+15n^4+10n^3-n}{30} \leq 16n^4 \\\\ \iff 6n^5+10n^3-n \leq 465n^4 \iff 465n^4-6n^5-10n^3+n\geq 0$

and, because $n \geq 0$ ,

$465n^4-6n^5-10n^3+n\geq 0 \iff n(465n^3-6n^4-10n^2+1)\geq 0 \\\iff 465n^3-6n^4-10n^2+1\geq 0 \iff 465n^3-6n^4-10n^2\geq -1\\\iff n^2(465n-6n^2-10)\geq -1$

Observe that, because $n \geq 2$ and is an integer,

$n^2(465n-6n^2-10)\geq -1 \iff 465n-6n^2-10 \geq 0 \iff n(465-6n) \geq 10\\\iff 465-6n \geq 0 \iff n \leq \frac{465}{6}=\frac{155}{2}=77.5$

In concusion, the statement is true if and only if n is a non negative integer such that $n\leq 77$

So, 78 is the smallest value of n that does not satisfy the inequality.

Note: If you compute $(4n)^4- \sum^{n}_{i=0} (2i)^4$ for 77 and 78 you will obtain:

$(4n)^4- \sum^{n}_{i=0} (2i)^4=53810064$

$(4n)^4- \sum^{n}_{i=0} (2i)^4=-61754992$

7 0

3 years ago

Solve issuing Pythagorean theorem

Anna35 [415]

Step-by-step explanation:

(8x8) + (16x16) = 64+256 = 320

√320 = 17.9

8 0

2 years ago

What is the completely factored form of f(x)=x3+5x2+4x−6?

Gre4nikov [31]

$f(x)=x^3+5x^2+4x-6$
$f(-3)=(-3)^3+5(-3)^2+4(-3)-6=0\implies x+3\text{ is a factor of }f(x)$

Synthetic division yields

-3 | 1   5   4   -6
.    |      -3 -6    6
- - - - - - - - - - - - -
.    | 1   2 -2    0

which translates to

$\dfrac{x^3+5x^2+4x-6}{x+3}=x^2+2x-2$

with remainder 0. Now by the quadratic formula,

$x^2+2x-2=0\implies x=\dfrac{-2\pm\sqrt{2^2-4(1)(-2)}}2=-1\pm\sqrt3$

and so

$f(x)=x^3+5x^2+4x-6=(x+3)(x-(-1+\sqrt3))(x-(-1-\sqrt3))$

3 0

3 years ago

GUYS HELP ME PLS. Tina is standing at the bottom of a hill. Matt is standing on the hill so that when Tina's line of sight is

Pie

Answer:

71°

Step-by-step explanation:

The angle of elevation of the hill can be obtiaed using trigonometry :

Given

the opposite length = 14.5 feets

Adjacent = 5 feets

The angle of elevation vabnbe obtained using :

Tan θ = opposite / Adjacent

Where θ = angle of elevation

Tan θ = 14.5 / 5

Tan θ = 2.9

θ = tan^-1(2.9)

θ = 70.97 = 71°

3 0

3 years ago