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4 years ago

Please help! Will give branliest for correct answer ! God Bless uu!!

Mathematics

2 answers:

mafiozo [28]4 years ago

8 0

Answer:

Solution given:.

area of traingle EFG=1/2b×h=1/2×7×6=21cm²

area of rectangle ABCD=l×b=(20+9)×7=203cm²

area of rectangle BHIJ=l×b=9×11=99cm²

Total area =21+203+99=323cm² is a required answer

katen-ka-za [31]4 years ago

5 0

323 cm squared is the answer

Top rectangle: 9x18= 162
Lower rectangle: 20x7=140
Triangle: 1/2bh = 1/2(6)(7) = 21

162+140+21 = 323 cm squared

You might be interested in

Find the quotient: 27y4 + 36y —————— -9y

liraira [26]

Answer: $-3y^3 -4$

Step-by-step explanation:

$\frac{27y^4 + 36y}{-9y}=-3y^3 -4$

8 0

2 years ago

Julio wants to break his school’s scoring record of 864 points during his 24-game basketball season. During the first 8 games of

Scilla [17]

Answer:

x≥38 points

Step-by-step explanation:

Julio wants to break his school’s scoring record of 864 points during his 24-game basketball season. During the first 8 games of the season, he scored a total of 256 points. Which inequality can be used to find x, the number of points Julio must average per game during the rest of the season to break the record?

julio has a 24 game basketball season.

he has played 8, it means there are 16 more games to go

therefore=

he has scored 256 nts, wic means there are still 608 points to go .

864-256=608

x is the points he more score per every game.

16x=608

to break the records ,he must score an extra point 1

so 16x≥608

x≥38

8 0

3 years ago

Read 2 more answers

How many can 2 go into 600

algol [13]

300 is the answer because it’s 600/2

6 0

3 years ago

Read 2 more answers

NEED HELP PLZ 45 POINTS

harina [27]

No because you need another angle. angle QRP and TRS are congruent because they are vertical angles. if you add that then you will get ASA which proves congruency

7 0

3 years ago

Read 2 more answers

In a game called taxation and evasion, a player rolls a pair of dice. if on any turn the sum is 7, 11, or 12, the player gets au

bezimeni [28]

The probability that she gets audited no more than 2 times is 0.896482...

As, a pair of dice are rolling here, so the number of total possible outcome = (6×6) = 36

For Sum = 7 , the favorable outcomes are: (1,6) (2,5) (3,4) (4,3) (5,2) and (6,1)

For Sum = 11 , the favorable outcomes are: (5,6) and (6,5)

For Sum = 12 , the favorable outcome is: (6,6)

Probability = (Number of favorable outcomes)÷(Number of total outcomes)

So, $P(7)= \frac{6}{36} =\frac{1}{6}$

$P(11) = \frac{2}{36} = \frac{1}{18}$

$P(12) = \frac{1}{36}$

P( 7 or 11 or 12) = $\frac{1}{6}+\frac{1}{18}+\frac{1}{36} = \frac{6+2+1}{36}=\frac{9}{36} = \frac{1}{4}$

Here the total number of trials = 5 and the probability of getting audited = $\frac{1}{4}$

According the binomial distribution formula:

P(X) = (ⁿCₓ )(P)ˣ (1-P)ⁿ⁻ˣ

where P(X) is the probability of x successes out of n trials

Here, n= 5 and P = 1/4 and we need to find the probability of getting audited no more than 2 times. This means she can gets audited 0, 1 or 2 times.

So,

$P(X=0)+P(X=1) +P(X=2)\\\\= [^5C^0 (\frac{1}{4})^0 (1-\frac{1}{4})^5^-^0 ]+[^5C^1 (\frac{1}{4})^1 (\frac{3}{4})^5^-^1]+[^5C^2 (\frac{1}{4})^2 (\frac{3}{4})^5^-^2]\\\\= (\frac{3}{4})^5+ (5) (\frac{1}{4}) (\frac{3}{4})^4 +(10)(\frac{1}{4})^2 (\frac{3}{4})^3\\\\=0.237304... +0.395507...+0.263671...\\\\ = 0.896482...$

So, the probability that she gets audited no more than 2 times is 0.896482...

5 0

3 years ago