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3 years ago

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When sending a file as an e-mail attachment, the save & send option can be found by clicking on which tab? insert file home

insert

Computers and Technology

1 answer:

aleksklad [387]3 years ago

5 0

I belive that it is .insert.

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Edhesive assignment 4

Agata [3.3K]

Answer:

nrToCheck = int(input("How many numbers do you need to check? "))

nrEven = 0

nrOdd = 0

for i in range(nrToCheck):

number = int(input("Enter number: "))

if (number % 2):

nrOdd = nrOdd + 1

print("{} is an odd number".format(number))

else:

nrEven = nrEven + 1

print("{} is an even number".format(number))

print("You entered {} even number(s).".format(nrEven));

print("You entered {} odd number(s).".format(nrOdd));

7 0

3 years ago

Methods are used to define an object's behavior. True False

pishuonlain [190]

Answer: True

Explanation:

Yes, the given statement is true that the methods are use to define an object behavior. As, methods are basically a procedure which are associated with the an object, where an object are the combination of functions and variable.

An object is basically consist of behavior and data in which the data are used to represent the properties of an object and the behavior are used to represent the methods of an object.

Methods maintain the interface for modifying the properties of data in an object.

4 0

4 years ago

What is the first thing you should do when creating a spreadsheet

sashaice [31]

First decide what the rows will represent and what the columns will represent. If you aren't sure use "transpose".

3 0

3 years ago

A _____, or spider, is a search engine program that automatically searches the web to find new websites and update information a

Len [333]

Answer: B) Web robot

Explanation:

Web robot or spider is the search engine program which automatically visit the new web site and update the information. Basically, it is the internet bot that helps in store the information from the search engine to the index.

Spider searches the web site and read the information in their given page for creating the entries from search engine.

Web robot is also known as web crawler, this type of programs are use by different search engine that automatically download and update the web content on web sites.

3 0

4 years ago

A person gets 13 cards of a deck. Let us call for simplicity the types of cards by 1,2,3,4. In How many ways can we choose 13 ca

natima [27]

Answer:

There are 5,598,527,220 ways to choose <em>5</em> cards of type 1, <em>4 </em>cards<em> </em>of type 2, <em>2</em> cards of type 3 and <em>2</em> cards of type 4 from a set of 13 cards.

Explanation:

The <em>crucial point</em> of this problem is to understand the possible ways of choosing any type of card from the 13-card deck.

This is a problem of <em>combination</em> since the order of choosing them does not matter here, that is, the important fact is the number of cards of type 1, 2, 3 or 4 we can get, no matter the order that they appear after choosing them.

So, the question for each type of card that we need to answer here is, how many ways are there of choosing 5 cards of type 1, 4 cards of type 2, 2 cards of type 3 and 2 are of type 4 from the deck of 13 cards?

The mathematical formula for <em>combinations</em> is $\\ \frac{n!}{(n-k)!k!}$ , where <em>n</em> is the total of elements available and <em>k </em>is the size of a selection of <em>k</em> elements from which we can choose from the total <em>n</em>.

Then,

Choosing 5 cards of type 1 from a 13-card deck:

$\frac{n!}{(n-k)!k!} = \frac{13!}{(13-5)!5!} = \frac{13*12*11*10*9*8!}{8!*5!} = \frac{13*12*11*10*9}{5*4*3*2*1} = 1,287$ , since $\\ \frac{8!}{8!} = 1$ .

Choosing 4 cards of type 2 from a 13-card deck:

$\\ \frac{n!}{(n-k)!k!} = \frac{13!}{(13-4)!4!} = \frac{13*12*11*10*9!}{9!4!} = \frac{13*12*11*10}{4!}= 715$ , since $\\ \frac{9!}{9!} = 1$ .

Choosing 2 cards of type 3 from a 13-card deck:

$\\ \frac{n!}{(n-k)!k!} =\frac{13!}{(13-2)!2!} = \frac{13*12*11!}{11!2!} = \frac{13*12}{2!} = 78$ , since $\\ \frac{11!}{11!}=1$ .

Choosing 2 cards of type 4 from a 13-card deck:

It is the same answer of the previous result, since

$\\ \frac{n!}{(n-k)!k!} = \frac{13!}{(13-2)!2!} = 78$ .

We still need to make use of the <em>Multiplication Principle</em> to get the final result, that is, the ways of having 5 cards of type 1, 4 cards of type 2, 2 cards of type 3 and 2 cards of type 4 is the multiplication of each case already obtained.

So, the answer about how many ways can we choose 13 cards so that there are 5 of type 1, there are 4 of type 2, there are 2 of type 3 and there are 2 of type 4 is:

1287 * 715 * 78 * 78 = 5,598,527,220 ways of doing that (or almost 6 thousand million ways).

In other words, there are 1287 ways of choosing 5 cards of type 1 from a set of 13 cards, 715 ways of choosing 4 cards of type 2 from a set of 13 cards and 78 ways of choosing 2 cards of type 3 and 2 cards of type 4, respectively, but having all these events at once is the <em>multiplication</em> of all them.

5 0

4 years ago