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3 years ago

Please help me and put the right anwser pls

Mathematics

1 answer:

evablogger [386]3 years ago

7 0

Answer:

Its letter A

the first one

Step-by-step explanation:

when it a big negative number it makes it the smallest

so it goes -418,-86,-66,-15

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Snowcat [4.5K]

Hi!

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Area of a triangle = $(base * height)/2$

Area of a square = $(side)^2$

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QUESTION 1: Determine the area of the triangular face.

$\frac{bh}{2}$

$32(20)/2$

$640/2$

$320$

The triangular face is 320 square feet.

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QUESTION 2: Determine the surface area of the entire figure.

$a^2$

$32^2$

$1024$

Now, add the 4 triangular faces to the area of the square face.

$1024+320(4)$

$1024+1280$

$2304$

The total surface area is 1204 square feet.

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For more information, see:

brainly.com/question/4637102

brainly.com/question/22971514

5 0

3 years ago

Miguel draws a square on a coordinate plane. One vertex is located at (5,4). The length of each side is 3 units. Circle the lett

Ulleksa [173]

Answer:

A, B, and E.

Step-by-step explanation:

We know that one vertex is at (5, 4), and each side of our square is 3 units long.

Then the distance between the known vertex and another vertex is 3 units (if those vertexes are connected by a side of the square) or (√2)*3 units (if those vertexes are connected by the diagonal of the square).

Also remember that the distance between two points (a, b) and (b, c) is:

distance = √( (a - c)^2 + (b - d)^2)

So we need to find the distance between our point and all the ones given in the options:

A) the distance between (5, 4) and (5, 1) is:

distance = √( (5 - 5)^2 + (4 - 1)^2) = 3

Then point (5, 1) can be a vertex.

B) The distance between (5, 4) and (5, 7) is:

distance = √( (5 - 5)^2 + (4 - 7)^2) = 3

Then (5, 7) can be a vertex.

C) The distance between (5, 4) and (7, 8) is:

distance = √( (5 - 7)^2 + (4 - 8)^2) = √( 2^2 + 4^2) = √20

Point (7, 8) can not be a vertex.

D) The distance between (5, 4) and (2, 6) is:

distance = √( (5 - 2)^2 + (4 - 6)^2) = √( 3^2 + 2^2) = √13

Point (2, 6) can not be a vertex.

E) The distance between (5, 4) and (2, 1) is:

distance = √( (5 - 2)^2 + (4 - 1)^2) = √( 3^2 + 3^2) = √18 = √(2*9) = √2*√9 = √2*3

Then point (2, 1) can be a vertex.

8 0

3 years ago

How to do arithmetic sequence with fractions I’m so confused

Aleks [24]

Answer:

Step-by-step explanation:

first you have to see itis an arithmetic or geometric sequence.

then find common difference(for A.P) or common ratio (for G.P)

c.d .=an-an-1

c.r. =an/an-1

1.G.P.

2. A.P

3.G.P

3,5,25/3,125/9,...

c.r.=5/3

or (25/3)/5=25/(3*5)=5/3

or 125/9÷25/3=125/9×3/25=(125×3)/(9×25)=5/3

3 0

3 years ago

A bookstore had 45 copies of a magazine. Yesterday, it sold 2/3 of them. Today, it sold 1/3 of what remained. How many copies do

Ket [755]

After the first day, 1/3 of the original amount remained:

... (1/3)·45 = 15

After the second day, 2/3 of that amount remained:

... (2/3)·15 = 10

The bookstore has 10 copies left.

6 0

4 years ago

Resuelve las ecuaciones x+y=47 x+2y=79

iragen [17]

Hope this is how your suppose to do it .

6 0

3 years ago