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3 years ago

Please helppp me!!!!!

Mathematics

1 answer:

Scrat [10]3 years ago

7 0

Answer:

Step 2 contains error in the given problem.

Step-by-step explanation:

Given expression is:

$\frac{1}{2}x-3=\frac{1}{3}x+6$

Step 1: identifying the LCM.

The LCM identified is 6.

This step is correct.

In the next step, we multiply the LCM with each term of the equation.

Step 2:

$\frac{6}{1}(\frac{1}{2}x) -3 =\frac{6}{1}(\frac{1}{3}x)+6$

However,

In the given solution, the LCM is not multiplied with each term.

Hence,

Step 2 contains error in the given problem.

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Why are there two solutions for the equation |6 + y| = 2? Explain.

GaryK [48]

$Solution, \left|6+y\right|=2\quad :\quad y=-8\quad \mathrm{or}\quad \:y=-4$

$Steps:$

$|f\left(y\right)|=a\quad \Rightarrow \:f\left(y\right)=-a\quad \mathrm{or}\quad \:f\left(y\right)=a, 6+y=-2\quad \quad \mathrm{or}\quad \:\quad \:6+y=2$

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$\mathrm{Combine\:the\:ranges}, y=-8\quad \mathrm{or}\quad \:y=-4$

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4 years ago

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Dmitrij [34]

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Step-by-step explanation:

Given: 2x – 4y + 6 + 3x – 9y – 4

Combine all like terms:

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3 years ago

Y= x +2 and y=3x-4 solved using substitution

weqwewe [10]

So I did this:

y=x +2
y=3x-4

I used the first equation to plug into the second equation.
x+2= 3x -4
I subtracted 3 from both sides so I get
-2x+2=-4
So I subtract 2 from both sides so I get
-2x=-6
I divide -2 on both sides and so I get
x=3
Then I plug the x into either equation. I did the first equation.
y=3+2
y=5
So x=3 and y=5

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3 years ago