Answer:
The distance between B and lighthouse is 3.8688 km
Step-by-step explanation:
Given:
The angle made from ship to lighthouse is 36.5 degrees
and that of point B is 73 degrees.
To Find:
Distance Between Point B and Lighthouse
Solution:
<em>Consider a triangle LAB(Refer the attachment )</em>
And Point C is on the line AB as A i.e. ship is sailing to B
So C is at 5 km from A.
Now In triangle LAC,
Using Trigonometry Functions as ,
tan(36.5)=LC/AC
LC=tan(36.5)*AC
=0.7399*5
=3.6998 km
Now In triangle LBC,
As,
Sin(73)=LC/LB
LB=LC/(Sin(73))
=3.6998/0.9563
=3.8688 km
LB=3.8688 km
Answer:
5/(y+5)
Step-by-step explanation:
Perhaps you want the sum ...

_____
<em>Comment on rational expressions</em>
When writing ratios in plain text, it is imperative to put parentheses around numerators and denominators. (If the numerator is a product only, then parentheses are optional.)
Your expression might be properly written as ...
3y/(y^2 +7y +10) +2/(y+2)
As you have written it, it simplifies to ...
3(y/y)2 +7y +10 +2/y +2 = 3·2 +7y +2/y +12
= 7y +2/y +18
Please note, too, the exponentiation symbol (^).
Answer:
1. According to the angle bisector theorem, DAC = BAC
2. Same kind of goes for BC
3. X must be equal in both equations. x= 3
9(3) -7 = 20
4(3) +8 = 20
Hope this helped!