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Zarrin [17]
3 years ago
9

What is 7/6 as a mixed number

Mathematics
2 answers:
Sidana [21]3 years ago
8 0
7/6

6 can go into 7 once

1 and 1/6

Answer: 1  1/6
valina [46]3 years ago
8 0
7/6 as a mixed number:
you divide 6 into 7 like this:
                 _____
             6  I 7
Now, 7 divided by 6 equals 1, but there is a remainder. THAT REMAINDER WILL BECOME YOUR NEW NUMERATOR NEXT TO ONE! The divisor, (6), will become your NEW denominator, and this will be your new mixed number:
     1            One and one/sixth. I hope I helped! :-)
 1 __
     6
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Calculate the perimeter of the figure below.
mote1985 [20]

Well, we know perimeter is just adding all the lengths together.

And we already know 2 of the lengths, so we know the rest. 11 1/2 is the same as the opposite side, and 6 1/3 is the same as the opposite side.

So the sides are 6 1/3, 6 1/3, 11 1/2, 11 1/2.

Add them up:

6 1/3 + 6 1/3 + 11 1/2 + 11 1/2.

Improper fractions:

19/3 + 19/3 + 23/2 + 23/2.

Common denominator, (6):

38/6 + 38/6 + 69/6 + 69/6 = 214/6.

Simplify:

214/6 =  35 2/3

7 0
3 years ago
Please help me out on here! Will give brainlest
laiz [17]

Answer:

7)

Step-by-step explanation:

The pattern is: add two more than you did before: starting from 2.

It would be:

1, 3, 7, 13,  21,  31, 43, 57

+2 +4 +6 +8 +10  +12  +14

Now use this to answer the questions.

Hope this helped!

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6 0
2 years ago
Solve for x .<br><br> 18 ÷ x = -2 <br> x =
Ratling [72]
X would equal -9
Because -9 times -2 equals 18
5 0
3 years ago
Read 2 more answers
At six am the temperature was -8°c at noon the temperature was 3°c what was the change in temperature between 6 am and noon
Roman55 [17]
The temperature change from 6am to noon is 11°c
4 0
3 years ago
Average Temperatures Suppose the temperature (degrees F) in a river at a point x meters downstream from a factory that is discha
mr Goodwill [35]

Answer:

Step-by-step explanation:

Average Temperatures Suppose the temperature (degrees F) in a river at a point x meters downstream from a factory that is discharging hot water into the river is given by

T(x) = 160-0.05x^2

a. [0, 10]

For x = 0

T(0) = 160 - 0.05 × 0^2

T(0) = 160

For x = 10

T(10) = 160 - 0.05 × 10^2

T(10) = 160 - 5 = 155

The average temperature

= (160 + 155)/2 = 157.5

b. [10, 40]

For x = 10

T(10) = 160 - 0.05 × 10^2

T(10) = 160 - 5 = 155

For x = 40

T(10) = 160 - 0.05 × 40^2

T(10) = 160 - 80 = 80

The average temperature

= (80 + 155)/2 = 117.5

c. [0, 40]

For x = 0

T(0) = 160 - 0.05 × 0^2

T(0) = 160

For x = 40

T(10) = 160 - 0.05 × 40^2

T(10) = 160 - 80 = 80

The average temperature

= (160 + 80)/2 = 120

6 0
3 years ago
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