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shusha [124]
3 years ago
14

Consider two concentric cylinders with a Newtonian liquid of constant density, r, and constant dynamic viscosity, µ, contained b

etween them. The outer pipe, with radius, Ro, is fixed while the inner pipe, with radius, Ri, and mass per unit length, m, falls under the action of gravity at a constant speed. There is no pressure gradient within flow and no swirl velocity (i.e., tangential velocity) component. Determine the vertical speed, V, of the inner cylinder as a function of the following (subset of) parameters: g, Ro, Ri, m, r, and µ
Physics
1 answer:
exis [7]3 years ago
6 0
Ro ro
Rtf g the answer is no answer
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A car is strapped to a rocket (combined mass = 661 kg), and its kinetic energy is 66,120 J.
Katen [24]

Answer:

9.4 m/s

Explanation:

The work-energy theorem states that the work done on an object is equal to the change in kinetic energy of the object.

So we can write:

W=K_f - K_i

where in this problem:

W = -36.733 J is the work performed on the car (negative because its direction is opposite to the motion of the car)

K_i = 66,120 J is the initial kinetic energy of the car

K_f is the final kinetic energy

Solving for Kf,

K_f = W+K_i = -36,733+66,120=29,387 J

The kinetic energy of the car can be also written as

K_f = \frac{1}{2}mv^2

where:

m = 661 kg is the mass of the car

v is its final speed

Solving, we find

v=\sqrt{\frac{2K}{m}}=\sqrt{\frac{2(29,387)}{661}}=9.4 m/s

8 0
3 years ago
The average distance of the planet mercury from the sun is 0.39 times the average distance of the earth from the sun. How long i
Stels [109]

Answer:

T_1=0.24y

Explanation:

Using Kepler's third law, we can relate the orbital periods of the planets and their average distances from the Sun, as follows:

(\frac{T_1}{T_2})^2=(\frac{D_1}{D_2})^3

Where T_1 and T_2 are the orbital periods of Mercury and Earth respectively. We have D_1=0.39D_2 and T_2=1y. Replacing this and solving for

T_1^2=T_2^2(\frac{D_1}{D_2})^3\\T_1^2=(1y)^2(\frac{0.39D_2}{D_2})^3\\T_1^2=1y^2(0.39)^3\\T_1^2=0.059319y^2\\T_1=0.24y

5 0
3 years ago
John attaches a ball to a spring. The diagram below shows what happens. Which option shows the direction of the force of the bal
Vika [28.1K]
The answer is downwards because the ball is pulling down the spring due to its weight
8 0
3 years ago
Read 2 more answers
Which of the following quantities would be acceptable representations of weight? Check all that apply.
Oxana [17]

Only 12 lb and 1600 kN .

7 0
3 years ago
Puck A, of inertia mm, is attached to one end of a string of length ℓℓ , and the other end of the string is attached to a pivot
algol13

Answer:

L_{B} / L_{A} = \frac{5mvl}{mvl}= 5

Explanation:

Find the given attachment

8 0
3 years ago
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