Car A take a time of 2.55hr and car B take a time of 2.14 hr
We know that distance divide by time is speed
here it is given that car A to reach a gas station a distance 189 km from the school traveling at a speed of 74 km/hr
so speed=distance/time
s=d/t
t=d/s
=189/74
=2.55hr
In case of car B it is given that The distance from the is 199.8km, car b is traveling at a speed of 93 km/hr
s=d/t
t=d/s
=199.8/93
=2.14hr
so from the above given data and the formula we solved and found out the time taken by car A is 2.55h and car B is 2.14h
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Answer:
326149.2 KJ
Explanation:
The heat transfer toward and object that suffered an increase in temperature can be calculated using the expression:
Q = m*cv*ΔT
Where m is the mass of the object, cv is the specific heat capacity at constant volume, which basically means the amount of heat necessary for a 1kg of water to increase 1C degree in temperatur, and ΔT is the change in temperature.
A 65000 L swimming pool will have a mass of:
65000L *
= 65000 kg
The specific heat capacity at constant volume of water is equal to 4.1814 KJ/KgC.
We replace the data and get:
Q = m*cv*ΔT = 65000 kg * 4.1814 KJ/KgC * 1.2°C = 326149.2 KJ
Answer:
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Answer.
The road on the hills goes upward with the increasing length of the road.That's why we make a winding roads because it reduces the allover surface inclination in every portion of the road which is suitable for driving the vehicles.
