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Tema [17]
3 years ago
9

Convert 3 hours 21 minutes to decimal hours.

Physics
1 answer:
Oxana [17]3 years ago
7 0

Total hours is 3.35 hours

<u>Explanation:</u>

Given:

convert 3 hours 21 minutes to decimal hours

We know:

1 hour = 60 minutes

and

1 minute = 60 seconds

1 minute = 1 / 60 hours

So,

21 minutes = \frac{21}{60} hours

                  = 0.35 hours

Total hours would be = 3 hours + 0.35 hours

                                    = 3.35 hours

Therefore, total hours is 3.35 hours

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Where is the value of kinetic energy equal to zero
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if the object is not in motion

Explanation:

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A closed-end organ pipe is used to produce a mixture of sounds. The third and fifth harmonics in the mixture have frequencies of
nexus9112 [7]

Answer:

F_1=366.67Hz

Explanation:

From the question we are told that:

Frequency of 3rd harmonics F_3=1100

Frequency of 5th harmonics F_3=1833

Generally the equation for Wavelength at 3rd Harmonics is mathematically given by

 \lambda_3=\frac{4}{3}l

Therefore

 F_3=\frac{3v}{4l}

Generally the equation for Wavelength at 1st Harmonics is mathematically given by

 \lambda_1=\frac{4}{1}l

Therefore

 F_1=\frac{v}{4l}

Generally the equation for the frequency of the first harmonic is mathematically given by

 F_1=\frac{F_3}{3}

 F_1=\frac{1100}{3}

 F_1=366.67Hz

7 0
3 years ago
How was Mendeleev's table different from Meyer's table? A. Mendeleev did not arrange according to chemical properties. B. Meyer
olya-2409 [2.1K]

Answer: C. Meyer did not leave gaps while Mendeleev did.

Explanation: Mendeleev's table was table different from Meyer's table because Meyer did not leave gaps while Mendeleev did.

7 0
3 years ago
The cylinder in the picture is rotating at 500 RPMs. The friction coefficients between the cylinder and block B are static=0.5 a
Tju [1.3M]

  • Coefficient of static friction = 0.5
  • Coefficient of Kinetic friction = 0.3
  • Angular velocity = 500 RPMs

<h3>The Radius of the System</h3>

Let R be the radius of cylinder

m_a + m_b = 4 + 3 = 7kg

The angular velocity is 500 RPMs

\omega ^2 = \frac{500 * 2\pi}{60} rad/s\\N = (M_a + M_b)\omega ^2 R

The normal force

f = \mu N = (M_a + M_b) g\\\mu (M_a + M_b) \omega ^2 R = M_a + M_b\\R = \frac{1}{\mu \omega ^2 R}\\\mu_s = 0.5\\R = \frac{1}{0.5 * (\frac{500 * 2\pi}{60})^2 }\\R = 0.0073m\\R = 7.3mm

Since the radius is very little for two block to execute circular motion so system will slide down.

Learn more on coefficient of static friction here;

brainly.com/question/11841776

brainly.com/question/25772665

brainly.com/question/26400616

8 0
2 years ago
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