when the two waves interfere with eachother to make a dark spot the periodic difference of the two waves is π . the wave length for 2π is 600nm
. ie. for π difference it is 300nm
Last month, we featured IRB best practices (“IRBs: Navigating the Maze” November 2007 Observer), and got the ball rolling with strategies and tips that psychological scientists have found to work. Here, we continue the dissemination effort with the second of three articles by researchers who share their experiences with getting their research through IRB hoops. Jerry Burger from Santa Clara University managed to do the seemingly impossible — he conducted a partial replication of the infamous Milgram experiment. Read on for valuable advice, and look for similar coverage in upcoming Observers. These are the first words I said to Muriel Pearson, producer for ABC News’ Primetime, when she approached me with the idea of replicating Stanley Milgram’s famous obedience studies. Milgram’s work was conducted in the early 1960s before the current system of professional guidelines and IRBs was in place. It is often held up as the prototypic example of why we need policies to protect the welfare of research participants. Milgram’s participants were placed in an emotionally excruciating situation in which an experimenter instructed them to continue administering electric shocks to another individual despite hearing that person’s agonizing screams of protest. The studies ignited a debate about the ethical treatment of participants. And the research became, as I often told my students, the study that can never be replicated. Hope this helps!
This should be true, howl this helps
<span>If the temperature increases in a sample of gas at constant volume, then its pressure increases. The increase in temperature makes the molecule hit the walls of the container faster. The correct option among all the options that are given in the question is the third option or option "c". I hope the answer helps you.</span>
Answer:
323 m/s²
Explanation:
Given:
x₀ = 0 m
y₀ = 0 m
x = 29500 cos 65°
y = 29500 sin 65°
v₀x = 1810 cos 20°
v₀y = 1810 sin 20°
t = 9.20
Find:
ax, ay, θ
First, in the x direction:
x = x₀ + v₀ t + ½ at²
29500 cos 32° = 0 + (1810 cos 20°) (9.20) + ½ ax (9.20)²
25017 = 15648 + 42.32 ax
ax ≈ 221.4
And in the y direction:
y = y₀ + v₀ t + ½ at²
29500 sin 32° = 0 + (1810 sin 20°) (9.20) + ½ ay (9.20)²
15633 = 5695 + 42.32 ay
ay ≈ 234.8
Therefore, the magnitude of the acceleration is:
a² = ax² + ay²
a² = (221.4)² + (234.8)²
a ≈ 322.7
Rounded to 3 significant figures, the magnitude of the acceleration is approximately 323 m/s².
