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3 years ago

Evaluate (a + b) 2 for a = 2 and b = 3. 10 13 25

2 answers:

6 0

It is 10 Because (2+3)•2 is 10 this is how. First you start with the numbers in parentheses so (2+3) that equals 5 and then you multiply that by 2 and 5•2=10 which is your answer.

viva [34]3 years ago

5 0

Answer:

The answer is 25 because they are in parenthesis

Step-by-step explanation:

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Solve absolute value equation 2|x-3|-8=2

Semmy [17]

Answer:

$x=8, -2$

Step-by-step explanation:

$2|x-3|-8=2$

$2|x-3|=10$

$|x-3|=5$ $|x-3|=-5$

$x-3=5$ $x-3=-5$

$x=8$ $x=-2$

7 0

3 years ago

The lengths of pregnancies are normally distributed with a mean of days and a standard deviation of days. a. Find the probabilit

Alik [6]

Answer:

a) The probability of a pregnancy lasting X days or longer is given by 1 subtracted by the p-value of $Z = \frac{X - \mu}{\sigma}$ , in which $\mu$ is the mean and $\sigma$ is the standard deviation.

b) We have to find X when Z has a p-value of $\frac{a}{100}$ , and X is given by: $X = \mu - Z\sigma$ , in which $\mu$ is the mean and $\sigma$ is the standard deviation.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

In this question:

Mean $\mu$ , standard deviation $\sigma$

a. Find the probability of a pregnancy lasting X days or longer.

The probability of a pregnancy lasting X days or longer is given by 1 subtracted by the p-value of $Z = \frac{X - \mu}{\sigma}$ , in which $\mu$ is the mean and $\sigma$ is the standard deviation.

b. If the length of pregnancy is in the lowest a%, then the baby is premature. Find the length that separates premature babies from those who are not premature.

We have to find X when Z has a p-value of $\frac{a}{100}$ , and X is given by: $X = \mu - Z\sigma$ , in which $\mu$ is the mean and $\sigma$ is the standard deviation.

8 0

3 years ago

Helpppppppppppp ppppp:/

jeka94

Answer:

Step-by-step explanation:

I hope this helps

3 0

3 years ago

Al s cat weighs 6 3/5 pounds what is the weight of al,s cat written as a decimal

Tamiku [17]

The correct answer is C
to get 5 to 100, multiply by 20, so multiply 3 by 20 as well.

8 0

3 years ago

Expand (x-3)(x-8) to form a quadratic expression

AlladinOne [14]

Answer:

x^2 - 11x + 24

Step-by-step explanation:

Foil the equation

x^2 - 3x - 8x + 24

x^2 - 11x + 24

8 0

3 years ago