I hope this helps you
[20x^2/4x^2y]+[4xy^2/4x^2y]-[8y^2/4x^2y]
[5/y]+[y]-[4y/x^2]
I think we're not supposed to do more than 3 problems in one answer; certainly not five pages. Does the 1/3 mean there are 10 more to come?
I'll do the first page.
6)
Right triangle, opposite side of 10, adjacent side of 21,
tan x = opp/adj = 10/21
x = arctan 10/21 = 25.46°
Answer: 25
7)
cos x = adj / hyp = 10/14
x = arccos 10/14 = 44.42°
Answer: 44
8)
tan x = opp/adj = 12/24 = 1/2
x = arctan 1/2 = 26.57°
Answer: 27
9)
tan x = 31/32
x = arctan 31/32 = 44.09°
Answer: 44
10)
x = arctan 10/27 = 20.32°
Answer: 20
Find the domain by finding where the function is defined. The range is the set of values that correspond with the domain.
Domain: (- infinity, infinity)
Range: (- infinity, -2)
Answer:
(B) Write Negative 3 and one-third as Negative StartFraction 10 over 3 EndFraction, and find the reciprocal of StartFraction 4 over 9 EndFraction as StartFraction 9 over 4 EndFraction. Then, rewrite Negative 3 and one-third divided by StartFraction 4 over 9 EndFraction as Negative StartFraction 10 over 3 EndFraction times StartFraction 9 over 4 EndFraction. The quotient is Negative 7 and StartFraction 6 over 12 EndFraction = Negative 7 and one-half.
Step-by-step explanation:
To find the quotient of the division:
Step 1: 
Step 2: Find the reciprocal of 
