The set of inequalities y ≤ x² - 3 and y > -x² + 2 do not have a solution
<h3>How to modify the graphs</h3>
The attached figure 1 represents the missing piece in the question
From the graph, we have:
f(x) = x² - 3
g(x) = -x² + 2
Next, we change the equations to inequalities as follows:
y ≤ x² - 3
y > -x² + 2
To modify the graph, we then perform the following transformations:
- Shift the function g(x) down by 2 units
- Reflect across the x-axis
- Shift the function g(x) down by 3 units
<h3>How to identify the solution set</h3>
After the modifications in (a), we have:
y ≤ x² - 3 and y > -x² + 2
Next, we plot the graph of the inequalities
From the graph of the inequalities, the curves of the inequalities have no point of intersection
Hence, the set of inequalities do not have a solution
Read more about inequalities at:
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Answer:
I think its -48
Step-by-step explanation:
Answer:
Step-by-step explanation: just do it
Answer:the denominator stays the same and the numerator gets added or multiplied
Step-by-step explanation:
break it down
Answer:
The answer to your question is letter D
Step-by-step explanation:
Letter A. It is not possible because it is necessary to considers the variable (number of weeks)and this option does not consider it.
Letter B. It is not possible besides it consider the number of weeks the results do not correspond with the conditions given.
Example: for week 1, the number of freckles is 10 + 2¹ = 10 + 2 = 12, and the number of freckles must be 20.
Letter C. It is incorrect because the numbers of freckles do not correspond with the conditions.
Example: week 2 f = 2(10) ² = 2(100) = 200, it is higher than the expected.
Letter D. This is the correct answer because it satisfied the conditions given.
