Answer:
The probability that a defective rod can be salvaged = 0.50
Step-by-step explanation:
Given that:
A machine shop produces heavy duty high endurance 20-inch rods
On occasion, the machine malfunctions and produces a groove or a chisel cut mark somewhere on the rod.
If such defective rods can be cut so that there is at least 15 consecutive inches without a groove.
Then; The defective rod can be salvaged if the groove lies on the rod between 0 and 5 inches i.e ( 20 - 15 )inches
Now:
P(X ≤ 5) =
= 0.25
P(X ≥ 15) =
= 0.25
The probability that a defective rod can be salvaged = P(X ≤ 5) + P(X ≥ 15)
= 0.25+0.25
= 0.50
∴ The probability that a defective rod can be salvaged = 0.50
a. 48.467 miles
b. 19.8839 miles
c. 33.554 miles
1 kilometer is equal to 0.621371 miles (short = 0.62)
1 mile is equal to 1.609344 kilometers
Answer:
a) distance = 0.5m
b) acceleration = -1.25m/s²
Step-by-step explanation:
v = d/t
d = vt
d = 10/20
= 0.5
a = v/t
= -10/8
= -1.25
a is negative because in the last 8s the care decelerate
The y intercept is 0 and if it has to do with slope x is 6 over 1. rise over run.
I believe the answer to your question is b.