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3 years ago

Which expression is equal to 5/√11 A) 5√/11 B) 5√11/11 C) 55/11 D) 25/11

1 answer:

6 0

$\dfrac{5}{\sqrt{11}}=\dfrac{5}{\sqrt{11}}\times\dfrac{\sqrt{11}}{\sqrt{11}}=\dfrac{5\sqrt{11}}{\sqrt{11^2}}=\boxed{\dfrac{5\sqrt{11}}{11}}\\\\ \text{The answer is B.}$

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artcher [175]

Is the following definition of perpendicular reversible? If yes, write it as a true biconditional.

Two lines that intersect at right angles are perpendicular.

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B. Yes; if two lines intersect at right angles, then they are perpendicular.

C. Yes; if two lines are perpendicular, then they intersect at right angles.

D. Yes; two lines intersect at right angles if (and only if) they are perpendicular.

Your Answer would be (D)

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REF: 2-3 Biconditionals and Definitions

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3 years ago

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The value of $\frac{dx}{dt}$ is $\frac{160}{x^3}$ .

Step-by-step explanation:

The given equation is

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Differentiate with respect to t.

$4x^3\frac{dx}{dt}=8(5y^4)\frac{dy}{dt}-0$ $[\because \frac{d}{dx}x^n=nx^{n-1},\frac{d}{dx}C=0]$

$4x^3\frac{dx}{dt}=40y^4\frac{dy}{dt}$

It is given that y=2 and dy/dt=1, substitute these values in the above equation.

$4x^3\frac{dx}{dt}=40(2)^4(1)$

$4x^3\frac{dx}{dt}=40(16)(1)$

$4x^3\frac{dx}{dt}=640$

Divide both sides by 4x³.

$\frac{dx}{dt}=\frac{640}{4x^3}$

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Therefore the value of $\frac{dx}{dt}$ is $\frac{160}{x^3}$ .

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3 years ago

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4 years ago

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Alex787 [66]

The ordered pair that is not on the graph is (-4,46)

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4 years ago

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