Answer:
(the volume of the hemisphere has no units, so i will suppose that it is 6m^3)
For a sphere of radius R, the volume is:
V = (4/3)*pi*R^3
Where pi = 3.14
And a hemisphere is half of a sphere, then the volume of a hemisphere of radius R is:
V = (1/2)*(4/3)*pi*R^3
We know that the volume of the hemisphere is 6 m^3, then we have the equation:
6 m^3 = (1/2)*(4/3)*3.14*R^3
Now we can solve this for R.
6 m^3 = 2.1*R^3
∛(6 m^3/2.1) = R = 1.41 m
The radius of the hemisphere is 1.41m
Now we want to find the surface of a sphere with this radius (if the radius is the same, then the diameter is the same)
For a sphere of radius R, the surface is:
S = 4*pi*R^2
Then the surface of this sphere is:
S = 4*3.14*(1.41 m)^2 = 24.971 m^2
