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Triss [41]
3 years ago
7

Can someone please help me I've been stuck on this for so long​

Mathematics
2 answers:
Vilka [71]3 years ago
8 0

Answer:

x = -3, y=2

Step-by-step explanation:

x+3y =3

3y -2x =12

Solve the first equation for x

x = 3-3y

Substitute this into the second equation

3y -2(3-3y) =12

Distribute

3y -6 +6y =12

Combine like terms

9y -6 =12

Add 6 to each side

9y-6+6 =12+6

9y =18

Divide each side by 9

9y/9 =18/9

y = 2

Now find x

x = 3 -3y

x = 3-3(2)

x = 3-6

x = -3

Ne4ueva [31]3 years ago
6 0

Answer:

x = -3  y = 2

Step-by-step explanation:

x + 3y = 3

2x - 3y = -12

3x = -9

x = -3

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Suppose lines EF and GH are reflected over the line Y equals X to form the lines JK and LM which statement would be true about t
katrin [286]

Answer:

A) JK and LM will be parallel to each other.

Step-by-step explanation:

On reflection on y=x line the x co-ordinate changes with y co-ordinate and y co-ordinate changes with x co-ordinate

(x,y)\rightarrow (y,x)

Points on line EF

(0,6) , (-5,-2)

On reflection of this line on y=x the new points we get for line JK are

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Points on line GH

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On reflection on y=x line the new points we get for line LM are

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Slope of line JK

m=\frac{y_2-y_1}{x2-x1}\\m=\frac{(-5)-0}{(-2)-6} \\m=\frac{-5}{-8}=\frac{5}{8}

Slope of line LM

m=\frac{y_2-y_1}{x2-x1}\\m=\frac{(-9)-(-4)}{1-9} \\m=\frac{-9+4}{-8}=\frac{-5}{-8}\\m=\frac{5}{8}

For two line to be parallel, their slopes will be same.

m_{JK} =\frac{5}{8} , m_{LM}=\frac{5}{8}

Since slopes of lines JK and LM are same therefore we can say that these are parallel to each other.

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