Answer: 150
Step-by-step explanation:
Answer:
(−0.103371 ; 0.063371) ;
No ;
( -0.0463642, 0.0063642)
Step-by-step explanation:
Shift 1:
Sample size, n1 = 30
Mean, m1 = 10.53 mm ; Standard deviation, s1 = 0.14mm
Shift 2:
Sample size, n2 = 25
Mean, m2 = 10.55 ; Standard deviation, s2 = 0.17
Mean difference ; μ1 - μ2
Zcritical at 95% confidence interval = 1.96
Using the relation :
(m1 - m2) ± Zcritical * (s1²/n1 + s2²/n2)
(10.53-10.55) ± 1.96*sqrt(0.14^2/30 + 0.17^2/25)
Lower boundary :
-0.02 - 0.0833710 = −0.103371
Upper boundary :
-0.02 + 0.0833710 = 0.063371
(−0.103371 ; 0.063371)
B.)
We cannot conclude that gasket from shift 2 are on average wider Than gasket from shift 1, since the interval contains 0.
C.)
For sample size :
n1 = 300 ; n2 = 250
(10.53-10.55) ± 1.96*sqrt(0.14^2/300 + 0.17^2/250)
Lower boundary :
-0.02 - 0.0263642 = −0.0463642
Upper boundary :
-0.02 + 0.0263642 = 0.0063642
( -0.0463642, 0.0063642)
Answer:
Here,
length = 8m
height = 4m
4s = 15 per m^2
Now,
300 per meter = 300 * 15 per m^2
= 4500 per m^2
Answer:
y = -4x - 6
Step-by-step explanation:
12x + 3y = -18
Solve for y.
3y = -12x - 18
y = -12/3 x - 18/3
y = -4x - 6
Answer: A
Graph cut the horizontal and vertical axis at 2 points A(0;5) and B(1.66666;0)
you calc x=0 in the answer and have y
you can choose A or B. Next, you calc y=0 into A,B. If x=1.6666666, your answer is A
Sorry about my bad english
