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erastovalidia [21]
4 years ago
8

Find the reference angle for the given angle. Show your work. -404°

Mathematics
2 answers:
Mamont248 [21]4 years ago
6 0

Answer:

44°

Step-by-step explanation:

The reference angle is the magnitude of the smallest angle between the terminal ray and the x-axis.

Your angle is one full circle clockwise plus 44° more (-360° -44° = -404°), so makes an angle of -44° with respect to the positive x-axis. The magnitude of that is 44°.

_____

<em>Using a function</em>

The attachment shows a calculator function that can be used to find the reference angle for any angle. (Replace the value -404 with the angle of your choice.)

Katarina [22]4 years ago
3 0

Answer:

44 degrees.

Step-by-step explanation:

What the reference angle is asking for, is that when you rotate that amount of degrees(or radians), you want to find the angle when you connect it to the x-axis. For example, (the attachment) the angle 200 is the same as if you go 20 degrees from the left side of the x axis. So, the same applies if the angle is negative. Also, if you're angle(but it's positive) is bigger than 360, you can just ignore it because it is a full rotation. So 404 is bigger than 360, so we can ignore it. 404-360 is 44. So that means we really rotated -44, meaning we spun clockwise instead of counter clockwise. Now, since our positive angle(44) is less than 90, we are done. This is because if our reference angle is greater then 90, than we can just create a new angle because it would leak into another quadrant, meaning we can define a new reference. Hope this makes sense.



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The smallest object visible with your eyes is similar to the width of a piece of hair, which is 1×10−4 meters wide. Using an opt
Sloan [31]

Answer:

B. 5\times10^{2}

Step-by-step explanation:

We are told that the smallest object visible with our eyes is similar to the width of a piece of hair, which is 1\times 10^{-4} meters wide.

Using an optical microscope, we can see items up to 2\times 10^{-7} meters wide.

To find the objects we can see with our eyes are how much larger than the objects we can see with an optical microscope, we can set an equation as:

\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=\frac{1*10^{-4}}{2*10^{-7}}

Using the exponent rule of quotient \frac{a^m}{a^n}=a^{m-n} we will get,

\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=\frac{1}{2}*10^{-4-(-7)}

\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=0.5*10^{-4+7}

\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=0.5*10^{3}

\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=0.5*10\times 10^{3-1}

\text{The object we can see with our eyes}=5\times10^{2}*\text{The objects we can see with microscope}

Therefore, the objects we can see with our eyes are 5\times10^{2} times larger than the objects we can see with an optical microscope and option B is the correct choice.

3 0
3 years ago
Please Help Meh
Kitty [74]
The answers B.) positive
7 0
3 years ago
Is 5(2x-3y) and 10x-3y equivalent?
stiks02 [169]

Answer:

No

Step-by-step explanation:

Apply the distributive property to 5(2x - 3y):

Multiply 5 by each term inside the parentheses.

5(2x - 3y) = 10x - 15y

The other expression is 10x - 10y.

The terms 10x in both expressions are equal.

Since the term -15y is not equal to the term -10y, the expressions are not equivalent.

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3 years ago
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OverLord2011 [107]
You literally just need to click yes then call it a day it’s simple don’t worry too much :D
6 0
3 years ago
All of the following are equivalent except _____.
Ratling [72]
0.2 would be the answer.
6 0
3 years ago
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