The top one. they can't be expressed in a fraction or decimal
Answer:
(a/b)^3 times 2/(b^4)
or
2(a/b)^3times 1/(b^4)
or instead of 1/b^4 ------>b^-4
Step-by-step explanation:
Answer:
15
Step-by-step explanation:
It was very long
50/75 reduces to 2/3
10/15 reduces to 2/3
2/3 is 2/3
6/9 = 2/3
5/7 will not reduce
so ur answer is 5/7
4)
I:3x+4y=67
II:5x-y=35
to eliminate y when they are added one of the equations must contain -ay and the other +ay (with a being some number)
in this case we have in I already a positive term and in II a negative, but they have different numbers
by using multiplication (property of equations) we can multiply II by 4 so the negative and positive parts match
II*4: 20x-4y=140
when I and 4*II get added this results in
3x+20x+4y-4y=67+140
23x=207
5)
in this case I and II were added which can be seen in the left side of the equation((3x+4y)+(5x-y)=8x+3y), so to get the right side we have to also add the right sides 67+35=102
so the full equation would be:
8x+3y=102
