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mel-nik [20]
3 years ago
7

How do I figure out the sequence? (Fractions) *I GIVE THANKS

Mathematics
2 answers:
Serga [27]3 years ago
4 0
I don't have an idea about the 1st one but second one goes by subtracting 1/3
subtract 1/3 from 8 1/3 it's 8, subtract 1/4 from 8 it's 7 2/3. figuring out the patterns are simple most of the time bu you can get stuck sometimes, if you wanna get better, practice...
Oksana_A [137]3 years ago
3 0
You can work out the pattern by subtracting the first number from the second. So for the first one, 7 1/2 (Which is equal to 7 2/4, because 1/2 = 2/4) - 7 1/4 = 1/4, so you add a quarter each time
For the second one, 8 - 8 1/3 = -(1/3), so you subtract a third each time
Hope that helps and isn't too confusing!
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A square ABCD has the vertices A(n, n), B(n, -n), C(-n, -n), and D(-n, n). Which vertex is in Quadrant III?
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The answer is C because it's two negatives. Hope that helped
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Mean (Average): 4.84615

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Step-by-step explanation:

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Answer: It will be (B)

Step-by-step explanation:

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The twice–differentiable function f is defined for all real numbers and satisfies the following conditions: f(0)=3 f′(0)=5 f″(0)
Vladimir79 [104]

g(x)=e^{ax}+f(x)\implies g'(x)=ae^{ax}+f'(x)\implies g''(x)=a^2e^{ax}+f''(x)

Given that f'(0)=5 and f''(0)=7, it follows that

g'(0)=a+5

g''(0)=a^2+7

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h(x)=\cos(kx)f(x)+\sin x\implies h'(x)=-k\sin(kx)f(x)+\cos(kx)f'(x)+\cos x

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h(0)=\cos0f(0)+\sin0=f(0)=3

The slope of the line tangent to h(x) at (0, 3) has slope h'(0),

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Differentiating both sides of

4x^2+y^2=48+2xy

with respect to x yields

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4(2)^2+y^2=48+2(2)y\implies y^2-4y-32=(y-8)(y+4)=0\implies y=8

(ignoring the negative solution because we don't care about it)

The tangent to this curve at the point (x,y) has slope \dfrac{\mathrm dy}{\mathrm dx}. This tangent line is horizontal when its slope is 0. This happens for

\dfrac{y-4x}{y-x}=0\implies y-4x=0\implies y=4x

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