1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mel-nik [20]
3 years ago
7

How do I figure out the sequence? (Fractions) *I GIVE THANKS

Mathematics
2 answers:
Serga [27]3 years ago
4 0
I don't have an idea about the 1st one but second one goes by subtracting 1/3
subtract 1/3 from 8 1/3 it's 8, subtract 1/4 from 8 it's 7 2/3. figuring out the patterns are simple most of the time bu you can get stuck sometimes, if you wanna get better, practice...
Oksana_A [137]3 years ago
3 0
You can work out the pattern by subtracting the first number from the second. So for the first one, 7 1/2 (Which is equal to 7 2/4, because 1/2 = 2/4) - 7 1/4 = 1/4, so you add a quarter each time
For the second one, 8 - 8 1/3 = -(1/3), so you subtract a third each time
Hope that helps and isn't too confusing!
You might be interested in
Evaluate A2 for A = -4
vekshin1
Hello there!

Evaluate a²  for a = -4

The first step we need to do is replace a by -4

So we have (-4)²

Now what you have realize is that we need to multiply -4 by itself twice.

So it should looks like this:

-4 * -4

The rules says that when we have minus * minus, the answer is positive.

So we have -4 * -4 = 16

Answer: 16

I hope this helps!

Please let us know if you have other questions.

#Garebear
8 0
3 years ago
The lines have the same slopes and the same y-intercepts.
MissTica

Answer:

B is the correct answer

7 0
3 years ago
Read 2 more answers
9 friends share 6 cookies equally . what fraction of the cookies does each friend get
emmasim [6.3K]

the answer is each friend gets 2/3 cookie
5 0
3 years ago
Find the restricted values of x for the following rational expression. If there are no restricted values of x, indicate "No Rest
melamori03 [73]

Given rational expression is

-\frac{8x}{8x^2+2x}

Now we need to find the restricted values if any for this rational expression.

Restricted values means the possible values of the used variable (x) that will make denominator 0 as division by 0 is not defined.

So to find the restricted values, we just set denominator equal to 0 and solve for x

8x^2+2x=0

2x(4x+1)=0

2x=0 or 4x+1=0

x=0 or 4x=-1

x=0 or x=-1/4


Hence final answer is x=0, -1/4

3 0
4 years ago
the number of a certain company’s video stores can be approximated by the linear equation y=-264x+4682, where x is the number of
kogti [31]
This problem is incomplete, but I think I know the probable question. Normally, you should have been given the target number of the company's video stores, so that you can replace the value of y and solve for x. Once you solve for x, you add this to year 1990 then you can solve for the year at which you can reach your target value. Suppose y = 3500 stores.

3500 = -264x + 4682
3500 - 4682 = -264x
-1182 = -264x
x = 4.48 years

Technically, that is equal to 4 years. Hence, the year would be 1990+4 = 1994.
8 0
3 years ago
Other questions:
  • What is (4a)^2 without exponents?
    10·1 answer
  • 4 1/9 - 3 3/5 what is the answer to this question ?
    9·1 answer
  • What is the domain of
    13·1 answer
  • If there are 3 classrooms that each have 25 desks and there are a total of 87 students, how many more desks need to be added to
    13·2 answers
  • Which scale factors produce an expansion under a dilation of the original image?
    9·2 answers
  • Help asap<br><br><br> Factor completely.<br><br> x^2−5x−24<br><br> Enter your answer in the box.
    5·2 answers
  • Write a real-world problem with y=x(2)+2?
    13·1 answer
  • Can you please help me out
    9·2 answers
  • Find the distance between the two points in simplest radical form.<br> (-5,0) and (-9,9)
    7·2 answers
  • Condense the expression to the logarithm of a single quantity.
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!