All categories

3 years ago

What is the equation of the asymptote? f (x) = 3^x-5+1 y=?

Mathematics

1 answer:

Natasha_Volkova [10]3 years ago

4 0

The equation of the asymptote is $y=1$

Explanation:

The given equation is $f(x)=3^{x-5}+1$

We need to determine the horizontal asymptote of the equation.

The given equation is of the exponential function of the form $f(x)=c \cdot n^{a x+b}+k$ and has a horizontal asymptote $y=k$

Hence, from the above equation, the value of k is 1.

Therefore, we have,

$k=1$

Thus, the horizontal asymptote is $y=1$

Therefore, the asymptote of the equation is $y=1$

You might be interested in

Can u answer this question?

Sonja [21]

Answer: 140

Step-by-step explanation:

If no. of apartments are y

35% of y = 49

Y = 4900/35 = 140

7 0

3 years ago

What is 7.25-6.17=? in subtracting decimals

Aleks04 [339]

Answer:

1.08

Step-by-step explanation:

5 0

3 years ago

CAN SOMEONE MULTIPLY THIS PLEASE, ITS URGENT

____ [38]

Let's factorise it :

$\: {\qquad \dashrightarrow \sf ( {x}^{3} - 5)(x + 3) }$

$\: {\qquad \dashrightarrow \sf {x}^{3} (x + 3) + [-5(x + 3)] }$

Using Distributive property we get :

$\: {\qquad \dashrightarrow \sf {x}^{3} + {3x}^{3} + ( - 5x - 15) }$

$\: {\qquad \dashrightarrow \sf {x}^{3} + {3x}^{3} - 5x - 15 }$

$\: {\qquad \dashrightarrow \sf 4{x}^{3} - 5x - 15 }$

⠀

Therefore,

$\: {\qquad \dashrightarrow \sf ( {x}^{3} - 5)(x + 3) =4{x}^{3} - 5x - 15}$

8 0

2 years ago

Solve for x in the triangle. Round your answer to the nearest tenth.

svetoff [14.1K]

Answer:

if angles shown are right angle then from corner to midpoint line if this is symettrical angles are 45 and 45. if area is asked of you need to

Step-by-step explanation:

To find the area of any right triangle, you simply multiply the lengths of the two sides that are perpendicular to each other, and then take half of that. if you could flip one of them and move it on top of the other, they would match exactly. The rectangle has an area of 2 × 4 = 8 square units.

6 0

3 years ago

Heyy pls help! worth 20 points, and please only help if you know the answer. also no links those r kinda annoying lol

iragen [17]

Step 1: Find the slope:

$m= \dfrac{y_2-y_1}{x_2-x_1}= \dfrac{-2-7}{4-(-2)} = \dfrac{-9}{6}= -\dfrac{3}{2}$

This gives you $y=-\dfrac{3}{2}x+b$ , but we need to find b.

To find b, substitute in one (x,y) pair and it doesn't matter which one. I'll go with (4,-2):

$\begin{aligned}-2&=-\dfrac{3}{2}(4)+b\\[0.5em]-2&=-6+b\\[0.5em]4&=b\end{aligned}$

Now take that b-value and plug in into the slope-intercept form:

$y=-\dfrac{3}{2}x+4$

It's always a good idea to toss in the other x-value from the other point, to make sure it checks out.

7 0

3 years ago