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agasfer [191]
3 years ago
11

Order the following from least to greatest -- 0.209, 0.039, 0.21, 0.045

Mathematics
1 answer:
Zinaida [17]3 years ago
5 0

Given numbers : 0.209, 0.039, 0.21, 0.045 .

In order to check the smallest number, we need to check tenth value of each number first.

0.209 has 2 in tenth place, 0.039 has 0 in tenth place, 0.21 has 2 in tenth place and 0.045 has 0 in tenth place.

In first step, we got two smaller numbers 0.039 and  0.045 because they both have 0 in tenth place and other two numbers 0.209 and 0.21 has 2's in tenth place.

Now, we will check hundredth place number in 0.039 and  0.045.

0.039 has 3 in it's hundredth place and 0.045 has 4 in it's hundredth place.

Therefore, 0.039 would be smallest number and 0.045 would be second smaller number.

Now, we woiuld check hundredth place number in 0.209 and in 0.21.

0.209 has 0 in it's hundredth place and 0.21 has 1 in it's hundredth place.

Therefore, 0.209 is smaller than 0.21 and third smaller number.

So, finally 0.21 would be greatest number.

So, the order from least to greatest is 0.039, 0.045, 0.209, 0.21 .

So, the order will be c < a < d < b.

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In a field of ducks and a dog someone counted 25 heads and 80 legs. How many dogs and ducks are there
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Ducks have 1 head. Dogs have 1 head.
Ducks have 2 feet. Dogs have 4 feet.

If x = no. of ducks and g = no. of dogs

x + g = 25
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Let's use substitution to solve.

x + g = 25 ⇒ x = 25 - g
replace x with 25 - g in the other equation and solve for g

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6 0
3 years ago
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motikmotik
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P URGENT I've got a timer going on but really need your help to answer this thank you!!
astraxan [27]

Given:

The radius of inner circle = 13 yd.

The width of the shaded region = 8 yd

To find the area of the shaded region.

Now,

The radius of the outer circle = 13+8 yd = 21 yd

Formula

The area of a circle of radius r unit is \pi r^{2} sq unit.

A = A_{1}-A_{2}

where, A = The area of the shaded region

A_{1} = Area of the outer region

A_{2}= Area of the inner region

Now,

A_{1}= \pi (21^{2})

A_{1} = (3.14)(21)(21)

A_{1}= 1384.74 sq yd

And,

A_{2} = \pi (13^{2})

A_{2} = (3.14)(13)(13)

A_{2}= 530.66 sq yd

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7 0
3 years ago
F(x) = 3x-1 and g(x)=2x^2
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Answer:

See below

Step-by-step explanation:

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(3x-1)-(2x^{2})=-2x^{2}+3x-1

c.  here you are to compose g into f.  In other words, pick up the whole g function and plug it into f wherever you see an x:

3(2x^{2} )-1=6x^{2} -1

d.  here you are compose f into g.  In other words, pick up the whole f function and plug it into g wherever you see an x:

2(3x-1)^2

You now have to FOIL out the (3x-1) like so:

2[(3x-1)(3x-1)]

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2(9x^{2} -6x+1)

Distribute in the 2 and you'll end up with the answer:

18x^{2} -12x+2

3 0
3 years ago
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