Answer:
True
Step-by-step explanation:
Quadratic equations have the highest degree on x as 2. The given equation has 3x^2, meaning that it is quadratic.
We have a triangle whose perimeter is 32 feet. Some information regarding the sides of the triangle is given:
GiveN:
- One side is 3 times the second side.
- Third side is 12 feet longer than the second side.
As we can see that, two sides of the triangle are defined the second sides. It means First and third side can be expressed in the form of second side.
- So let the second side be x
Then,
- First side = 3x
- And, third side = x + 12
We know that, perimeters is the sum of the lengths of all sides of the triangle, So it can be written as:

Solving it further,

Subtracting 12 from both sides,


Dividing 5 from both sides,


Then,
- First side = 3x = 12 feet
- Second side = 4 feet
- Third side = x + 12 = 16 feet
And we are done with the answer !!
#CarryOnLearning
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1/-5, because when x increases by 1, y decreases by 5
32 is the correct answer I believe if using PEMDAS method
Find the value of r(q(4)), so first you need to find the value of q(4).
q(4), this means that x = 4, so substitute/plug it into the equation to find the value of q(x) when x = 4:
q(x) = -2x - 1 Plug in 4 into "x" since x = 4
q(4) = -2(4) - 1
q(4) = -8 - 1
q(4) = -9
Now that you know the value of q(4), you can find the value of r(x) when x = q(4)
r(x) = 2x² + 1
r(q(4)) = 2(q(4))² + 1 Plug in -9 into "q(4)" since q(4) = -9
r(q(4)) = 2(-9)² + 1
r(q(4)) = 2(81) + 1
r(q(4)) = 163 163 is the value of r(q(4))