What is tan 11 pie/6
1 answer:
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<span>the limit as x approaches -3 of [g(x)-g(-3)]over(x+3) is the same as the derivative, or slope, of g(x) at the point x=-3, or g'(-3).
Since you are given the equation of the tangent line, the answer is just the slope of that line.
</span><span>2y+3=-(2/3)(x-3)
</span><span>6y+9=-2(x-3)
6y+9=-2x+6
6y=-2x-3
y= (-2x-3)/6
slope is -2/6 = </span>
Since you are given the equation of the tangent line, the answer is just the slope of that line.
</span><span>2y+3=-(2/3)(x-3)
</span><span>6y+9=-2(x-3)
6y+9=-2x+6
6y=-2x-3
y= (-2x-3)/6
slope is -2/6 = </span>
Answer:
314 square feet
Step-by-step explanation:
we know that
The area that will be covered by the spray of the quarter-circle sprinkler head, is equal to the area of a quarter circle with radius of 20 feet
so
The area of a quarter circle is
we have
substitute
Answer:
The cost of 1 doll = $ 7.5
and The Cost of 1 toy train = $ 5
Step-by-step explanation:
Let the price of 1 doll = $ x
The price of 1 toy train = $ y
Now, according to the question:
6 x + 2 y = $ 55
and 4 x + 7 y = $ 65
Solving the given system of equation,
From (1), we get
or, solving for y , we get
110y - 4y + 21 y = 195
or, 17 y = 85
⇒ y= 85/17 = 5
This implies : 6 x + 2 (5) =55
or, 6x = 55 - 10 = 45
or, x = 45/ 6 = 15/2
Hence, the cost of 1 doll = x = $ 7.5
and the Cost of 1 toy train = y = $ 5