D(-1,-1), E(-8,-4), F(-8,-8)
Answer:
1π
Step-by-step explanation:
suppose the radius of semicircle P is r,
then the radius of semicircle Q = (r+d)/2 ... d≤r
radius of semicircle R = (r-d)/2
area P = 1/2 (r)²π
area Q = 1/2 ((r+d)/2)² π = 1/8 (r² + 2rd + d²)π
area R = 1/2 ((r-d)/2)² π = 1/8 (r² - 2rd + d²)π
shaded area = P-Q-R = 1/2 r²π - 1/4 (r² + d²)π
= ((r² - d²)/4) * π
because there is no constant r value in the question and d value changes with the r change, when the vertical segment length equal the semicircle P radius (r), r=2 and d = 0
therefore the shaded area = ((2² -0²)/4)*π = 1π
Answer:
The 99% confidence interval for the mean number of toys purchased each year is between 7.6 toys and 7.8 toys.
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
![\alpha = \frac{1-0.99}{2} = 0.005](https://tex.z-dn.net/?f=%5Calpha%20%3D%20%5Cfrac%7B1-0.99%7D%7B2%7D%20%3D%200.005)
Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so ![z = 2.575](https://tex.z-dn.net/?f=z%20%3D%202.575)
Now, find M as such
![M = z*\frac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=M%20%3D%20z%2A%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
In which
is the standard deviation of the population and n is the size of the sample.
![M = 2.575*\frac{1.8}{\sqrt{7.7}} = 0.1](https://tex.z-dn.net/?f=M%20%3D%202.575%2A%5Cfrac%7B1.8%7D%7B%5Csqrt%7B7.7%7D%7D%20%3D%200.1)
The lower end of the interval is the sample mean subtracted by M. So it is 7.7 - 0.1 = 7.6 toys
The upper end of the interval is the sample mean added to M. So it is 7.7 + 0.1 = 7.8 toys
The 99% confidence interval for the mean number of toys purchased each year is between 7.6 toys and 7.8 toys.
Answer:
Simplified the answer is 3v
Step-by-step explanation:
Answer:
Step-by-step explanation:
the answer is a becuase it doesnt explain anything about being conguent