△BCD≅△GEF . If BC=10 , CD=3x+8 and EF=4x+6 , then what is the measure of CD ?
2 answers:
Given :-
ΔBCD ≅ ΔGEF
Then :-
∠B <=> ∠G ( ∠B = ∠G )
∠C <=> ∠E ( ∠C = ∠E )
∠D <=> ∠F ( ∠ D = ∠F )
BC <=> GE ( BC = GE )
CD <=> EF ( CD = EF )
BD <=> GF ( BD = GF )
Using this let us find CD .
CD = EF
Which means :-







Then :-
EF =

CD =

<h3>Therefore ,
CD = 14 .</h3>
Answer:
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