23 is negative correlation
You have to change the denominator of 6/10 into 100 then you will get 60/100 then you add 15/10+60/100
Answer:
(1, 4.5 )
Step-by-step explanation:
The required point is at the midpoint of AB
Use the midpoint formula
Given A(4, 3) and B(- 2, 6 ), then
midpoint = [ 0.5(4 - 2), 0.5(3 + 6) ] = (1, 4.5 )
You're looking for the largest number <em>x</em> such that
<em>x</em> ≡ 1 (mod 451)
<em>x</em> ≡ 4 (mod 328)
<em>x</em> ≡ 1 (mod 673)
Recall that
<em>x</em> ≡ <em>a</em> (mod <em>m</em>)
<em>x</em> ≡ <em>b</em> (mod <em>n</em>)
is solvable only when <em>a</em> ≡ <em>b</em> (mod gcd(<em>m</em>, <em>n</em>)). But this is not the case here; with <em>m</em> = 451 and <em>n</em> = 328, we have gcd(<em>m</em>, <em>n</em>) = 41, and clearly
1 ≡ 4 (mod 41)
is not true.
So there is no such number.
2x + 6 = 5
5x – 9 = 8x – 4
5x = 2y – 8
6b + 4 = 2
6 + 4 = 10
