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3 years ago

△BCD≅△GEF . If BC=10 , CD=3x+8 and EF=4x+6 , then what is the measure of CD ?

Mathematics

2 answers:

nignag [31]3 years ago

8 0

Given :-

ΔBCD ≅ ΔGEF

Then :-

∠B <=> ∠G ( ∠B = ∠G )

∠C <=> ∠E ( ∠C = ∠E )

∠D <=> ∠F ( ∠ D = ∠F )

BC <=> GE ( BC = GE )

CD <=> EF ( CD = EF )

BD <=> GF ( BD = GF )

Using this let us find CD .

CD = EF

Which means :-

$3x + 8 = 4x + 6$

$8 = 4x + 6 - 3x$

$8 = 1x + 6$

$1x + 6= 8$

$1x = 8 - 6$

$1x = 2$

$x = 2$

Then :-

EF =

$EF = 4x + 6 \\ = 4 \times 2 + 6 \\ = 8 + 6 \\ = 14$

CD =

$CD = 3x + 8 \\ = 3 \times 2 + 8 \\ = 6 + 8 \\ = 14$

<h3>Therefore , CD = 14 .</h3>

BabaBlast [244]3 years ago

7 0

Answer:

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Step-by-step explanation:

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