Answer:
The time taken for the projectile to reach the given height is 1.2 s.
Step-by-step explanation:
Given;
height of travel, h = 25 ft
initial velocity of the projectile, u = 15 ft/s
The time taken for the projectile to travel a height of 25 ft is given by the following kinematic equation;
h = ut + ¹/₂gt²
25 = 15t + ¹/₂(9.8)t²
25 = 15t + 4.9t²
4.9t² + 15t - 25 = 0
solving the quadratic equation, we will have the following solution of t;
t = 1.2 s
Therefore, the time taken for the projectile to reach the given height is 1.2 s.
When you evaluate the equation you plug in the numbers or replace the variables with the numbers it’s giving you.
-8(2)(-32) - 2(-8) + 4
-16(-32) - 16 + 4
512 + 20
= 532
Hope this helps!
Answer:
D
Step-by-step explanation:
Try to remember this formula.
Where a is the vertical multiplier, b is the horizontal multiplier, c is the x coordinate of the vertex, and d is the y coordinate of the vertex.
Since the vertex on the graph is (2,3), c and d have to be 2 and 3.
Also, there are no vertical/horizontal stretches so the a and b values stay at 1.
The final equation would come out to 
Answer:
its the last one
Step-by-step explanation:
Answer:
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