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3 years ago

13

A standard deck of 52 cards contains 4 aces. What is the probability of randomly drawing a card that is not an ace?

1 answer:

Stells [14]3 years ago

8 0

I There would be 52-4 = 48 cards that are not aces.

The probability of picking a non ace card would be 48 out of 52, which is written as 48/52, which reduces to 12/13

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$\huge\fcolorbox{blue}{aqua}{Answer:}$

═════════════════════

1. $- 5x - y = 8$

<h3>Solve for x</h3>

$-5x-y=8$

$-5x=8+y$

$-5x=y+8$

$\frac{-5x}{-5}=\frac{y+8}{-5}$

$x=\frac{y+8}{-5}$

$x=\frac{-y-8}{5}$

<h3>Solve for y</h3>

$-5x-y=8$

$-y=8+5x$

$-y=5x+8$

$\frac{-y}{-1}=\frac{5x+8}{-1}$

$y=\frac{5x+8}{-1}$

$y=-5x-8$

────────────────────

2. $-4x-y=2$

<h3>Solve for x</h3>

$-4x-y=2$

$-4x=2+y$

$-4x=y+2$

$\frac{-4x}{-4}=\frac{y+2}{-4}$

$x=\frac{y+2}{-4}$

$x=-\frac{y}{4}-\frac{1}{2}$

<h3>Solve for y</h3>

$-4x-y=2$

$-y=2+4x$

$-y=4x+2$

$\frac{-y}{-1}=\frac{4x+2}{-1}$

$y=\frac{4x+2}{-1}$

$y=-4x-2$

════════════════════

Explanation:

#Carry on learning

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