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Yuri [45]
1 year ago
11

Jaylynn draw a hen on graph paper using scale of 1 unit on her graph paper represents 5cm.The hen has height of 11 units in the

drawing.
What is the height,in cm,of the actual hen?

Answers:

A.33
B.44
C.55
D.66​
Mathematics
2 answers:
Elina [12.6K]1 year ago
4 0

Answer:

55

Step-by-step explanation:

1 unit = 5cm

we need to find out how much 11 units are so,

we multiply both sides: 1 unit *11  = 5cm*11,   11 units = 55 cm

             

lisabon 2012 [21]1 year ago
3 0

Answer:

55

Step-by-step explanation:

There are 11 units used on the paper. If each unit is 5cm, that means you can do 11*5 and get 55 cm.

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2 years ago
A box with an open top will be constructed from a rectangular piece of cardboard. The piece of cardboard is 10 inches wide and 1
kupik [55]

Answer:

Domain of the function is  { x : x∈R, x>0 } or (0,∞).

Step-by-step explanation:

It is given that the dimensions of a rectangular piece of cardboard are

Length = 14 inch

Width = 10 inch

The box will be constructed by cutting out equal squares of side x at each corner and then folding up the sides. So the dimensions of the box are

Length = 14-2x inch

Breadth = 10- 2x inch

Height = x inch

The volume of cuboid box is

V=length\times breadth \times height

The volume function of the box is

V=(14-2x)\times (10-2x)\times x

V=(14-2x)(10-2x)x

The volume function is V=(14-2x)(10-2x)x.

It is a polynomial function and domain of a polynomial function is all real numbers.

Here, x represents the height of the box. So, value of x must be a positive real number.

Domain of the function is

Domain = { x : x∈R, x>0 }

It can be written as (0,∞).

Therefore, domain of the function is  { x : x∈R, x>0 } or (0,∞).

5 0
3 years ago
The function H(t) = −16t2 + 60t + 95 shows the height H(t), in feet, of a projectile after t seconds. A second object moves in t
Dimas [21]
H(t) = -16t² + 60t + 95
g(t) = 20 + 38.7t

h(1) = -16(1²) + 60(1) + 95 = -16 + 60 + 95 = -16 + 155 = 139
h(2) = -16(2²) + 60(2) + 95 = -16(4) + 120 + 95 = -64 + 215 = 151
h(3) = -16(3²) + 60(3) + 95 = -16(9) + 180 + 95 = -144 + 275 = 131
h(4) = -16(4²) + 60(4) + 95 = -16(16) + 240 + 95 = -256 + 335 = 79

g(1) = 20 + 38.7(1) = 20 + 38.7 = 58.7
g(2) = 20 + 38.7(2) = 20 + 77.4 = 97.4
g(3) = 20 + 38.7(3) = 20 + 116.1 = 136.1
g(4) = 20 + 38.7(4) = 20 + 154.8 = 174.8

Between 2 and 3 seconds. 
The range of the 1st object is 151 to 131.
The range of the 2nd object is 97.4 to 136.1

h(t) = g(t) ⇒ 131 = 131

It means that the point where the 2 objects are equal is the point where the 1st object is falling down while the 2nd object is still going up. 
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3 years ago
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Answer:

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PLEASE HELP!!! The data set shows the ages of people riding a bus.
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