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hram777 [196]
3 years ago
14

A 2-column table with 4 rows. The first column is labeled x with entries 0, 0.5, 1, 1.5. The second column is labeled y with ent

ries 40, 39.25, 38.5, 37.75. What is the range of this function?
Mathematics
1 answer:
kodGreya [7K]3 years ago
4 0

help me help me help help me help

Step-by-step explanation:

You might be interested in
The coordinate m is 2.5 and mn=4. What are the possible coordinates for n
steposvetlana [31]
Refer to the figure shown below.

The coordinates of point m are (2,5).
Let (x,y) = the coordinates of pont n.

Because mn = 4, use the Pythagorean theorem to obtain
(x - 2)² + (y - 5)² = 4²

This represents a circle with center at (2,5) and radus = 4.

Answer:
Possible coordinates for n lie on the circle (x-2)² + (y-5)² = 16.

7 0
4 years ago
Help pls get it right bc Thais is a test
Reil [10]

Answer:

$0.11

Step-by-step explanation:

4 0
3 years ago
Kenji simplifies 3^5 x 4^ 5and gets the result 12^10, but Darlene is not sure. Is Kenji correct? Justify your answer.
V125BC [204]

That's a question about exponentiation.

Answer:

Kenji is wrong because he does not aply the porperty correctly.

Step-by-step explanation:

A exponetiation has this form:

\boxed{a^b}

<em>a </em>is the base

<em>b</em> is the power or exponent

To understand that situation it's important to know a property about exponentiation. When we have a multiplication with the same exponent and diferent bases, the result is the multiplication of the bases with the same exponent. Let's see this above, in mathematical language:

\boxed{a^b \cdot c^b = (a\cdot c) ^b}

Examples:

  • 2^3 \cdot 8^3 = (2 \cdot 8) ^3 = 16^3
  • 10^9 \cdot 23^9 = (10 \cdot 23) ^9 = 230^9

Now, we can say why Kenji is wrong. It's easy simplify 3^5 \cdot 4^5! We know that the result is (3 \cdot 4) ^5 = 12^5, but Kenji multiplied the bases and added the exponents, that's why he is wrong.

I hope I've helped. ^^

Enjoy your studies! \o/

3 0
3 years ago
What is the length of line segment AC is 8x-9.
Kruka [31]

Answer is ___ ___x=5.

7 0
3 years ago
Read 2 more answers
Points A and B lie on a circle centered at point O. If OA=5 and lenth of AB/circumference=1/4 what is the area of sector AOB? Us
MakcuM [25]
<h3>Given</h3>
  • arc AB of circle O is 1/4 of the circumference
  • radius of circle O is 5
  • pi is 3.14
<h3>Find</h3>
  • area of sector AOB
<h3>Solution</h3>

Since arc AB is 1/4 of the circumference, the central angle AOB will be 1/4 of a circle, so π/2 in radians. The area of a sector is given by

... A = (1/2)r²·θ

where θ is the central angle in radians and r is the radus.

The area is ...

... A = (1/2)·5²·π/2 = 25π/4

... A ≈ 19.625

The area of the sector is about 19.63 square units.

4 0
3 years ago
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