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uranmaximum [27]
4 years ago
12

How to find the length width height of a box that I'd 4 layers with 6 cubed in each

Mathematics
2 answers:
igor_vitrenko [27]4 years ago
8 0
You multiple how ever many layers you have. Like let's say you have 5 layers you would just go 6 times 6 times 6 and so on
zysi [14]4 years ago
4 0
I multiply those numbers and I got 24
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Share these amounts between Lin and Kuan-yin in the ratio given<br> $35 in the ratio 2 : 3
Taya2010 [7]

Answer:

2:3=14:21

Step-by-step explanation:

2+2=5

35/5=7

7*2=14

7*3=21

7 0
2 years ago
Read 2 more answers
Evaluate: 4!<br> Make sure to show your steps.
sergeinik [125]

Answer:

4! = 4 x 3 x 2 x 1

4! = 12 x 2 x 1

4! = 24 x 1

4! = 24

Let me know if this helps!

7 0
3 years ago
Read 2 more answers
Which sign makes the statement true? 97.3 ? 9.73 X 103 &lt; = /​
nataly862011 [7]

Answer:

<

Step-by-step explanation:

If you multiply a number then it becomes grater.

So you are multiplying 9.73 x 103 in the second statement.

The answer then is that since the 97.3 in the first section is the same number as the 97.3 in the second part.

The second part is bigger because it was multiplied and the first one stayed the same.  

5 0
3 years ago
Please help, best answer gets brainliest and 5 star rating
wariber [46]
Segment JI is a midsegment (given). So that means point J is a midpoint of segment HF. The midpoint cuts HF into two equal pieces. Those two pieces are HJ and JF. Therefore, HJ = JF

Using substitution, we can plug in the given expressions that the diagram shows. Then we can solve for x
HJ = JF
2x-3 = x+2
2x-3+3 = x+2+3
2x = x+5
2x-x = x+5-x
x = 5

Now that we know x = 5, use this to find the length of HG
HG = 11*x + 5
HG = 11*5 + 5
HG = 55 + 5
HG = 60

So HG is 60 inches long, which is the final answer

Note: 60 inches = 5 ft
6 0
4 years ago
I need help with exercises 3,4, and 6 please show all work and don’t answer number 5 just tell me if it is correct
joja [24]
*If you need me to do #5, DM me!

3. 
The area of a triangle can be given by (just plug and chug as always):
A_t = \frac{1}{2} bh = \frac{1}{2}(3)(4) = 6ft^2
The area of the triangle is 6ft².

4. I will divide into a triangle and a rectangle (because the actual equation for the area of a pentagon requires it to be a perfect pentagon). Let's do the triangle first (height is 3 because you subtract 12 from 15):
A_t = \frac{1}{2} bh = \frac{1}{2}(8)(3) = 12m^2
A_r = bh = 12(8) = 96m^2
Now we just add them:
96+12 = 108m^2

So, the area of that pentagon is 108m².

5. You are actually wrong on this one because the area of a triangle is:
A_t = \frac{1}{2}bh
So, just halve your answer and it will be correct.

6. We can just split it into 4 triangles of equal area and then multiply the area of 1 triangle by 4 to get the total area. Let's do just that:
A_t = \frac{1}{2}bh = \frac{1}{2}(2.5)(5) = 6.25cm^2
Multiply by 4 to get total area:
6.25*4 = 25cm^2

So, the area of the given rhombus is 25cm².
8 0
4 years ago
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