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3 years ago

HELP PLEASE!!!!❕❕❕write in standard form an equation of the line slope= 2/5;(-1,3)

Mathematics

2 answers:

Vinil7 [7]3 years ago

7 0

Answer: 2x - 5y = -17

Step-by-step explanation: Let's use the point-slope formula.

The point-slope formula is written y - y₁ = m(x - x₁).

In this formula, (x₁, y₁) is our point and <em>m</em> is our slope.

Now let's plug all our information into the formula.

So we have y - 3 = 2/5(x + 1).

Notice that I put x + 1 inside the parenthses and this

is because we have x minus a negative 1 which means x + 1.

Our next step would be to distribute this 2/5through both

terms inside the parenthses to get 2/5x + 2/5 on the right side.

So we have y - 3 = 2/5x + 2/5.

Now in standard form, we cannot have any fractions.

We need to get rid of them by multiplying

both sides of the equation by 5.

When we do this, we get 5y - 15 = 2x + 2.

Now we just move our number to the right by

adding 15 to both sides of the equation.

That gives us 5y = 2x + 17.

Move our 2x to the left side by subtracting

2x from both sides to get -2x + 5y = 17.

In standard form, the coefficient of the x term must be positive.

So our last step is to divide both sides

by -1 so that our answer is 2x - 5y = -17.

Anika [276]3 years ago

3 0

Answer:

2x-5y = -17

Step-by-step explanation:

Using point slope form

y-y1 = m(x-x1)

where m is the slope and (x1,y1) is the point on the line

y-3 = 2/5(x- -1)

y-3 = 2/5(x+1)

Multiply each side by 5 to clear the fraction

5(y-3) = 5* 2/5(x+1)

Distribute

5y-15 = 2x+2

Standard form is Ax + By = C where A is a positive integer and B and C are integers

Subtract 5y from each side

-15 = 2x-5y +2

Subtract 2 from each side

-17 = 2x-5y

2x-5y = -17

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Answer:

14 hours

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Let's call the task 3x

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3 years ago

What 2 numbers add up to get 17 and multiply to get -200

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There is no fixed equation when I arrived at these numbers.

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3 years ago

You work with the office of city planning which is currently evaluating a new contract for a major highway. The chosen contracto

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Answer:

0.5488 = 54.88% probability that there are no defects in the completed highway.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

The portion of highway that your city is building is 30 miles long.

The mean is one defect per 50 miles. Since the highway is 30 miles, we have that:

$\mu = \frac{30}{50} = 0.6$

What is the probability that there are no (0) defects in the completed highway?

This is P(X = 0). So

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-0.6}*0.6^{0}}{(0)!} = 0.5488$

0.5488 = 54.88% probability that there are no defects in the completed highway.

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3 years ago