Step-by-step explanation:
in ∆TUW & ∆VWU
∠UTW = ∠UVW (data / given)
WU = WU (common sides) ∠TWU = ∠VUW (TW//UV alternate∠ )
so ∆TUW & ∆VWU are congruent
Answer: 42 yards :)
Step-by-step explanation:
So
a be first term and d be common difference
- a+a+2d+a+4d+a+6d+a+9d=17
- 5a+21d=17--(1)
And
- a+d+a+3d+a+5d+a+7d+a+9d=15
- 5a+25d=15--(2)
Eq(1)-Eq(2)
Put in second one
- 5a+25d=15
- a+5d=3
- a+5/2=15
- a=15-5/2
- a=25/2
Answer: True.
Step-by-step explanation:
Answer:
(5x² +7x -26) units²
Step-by-step explanation:

Area of shaded region
= Area of larger rectangle -area of smaller rectangle
Area of larger rectangle
= (3x -4)(2x +2)
= 3x(2x) +3x(2) -4(2x) -4(2) <em>(</em><em>Expand</em><em>)</em>
= 6x² +6x -8x -8
= 6x² -2x -8
Area of smaller rectangle
= (x -6)(x -3)
= x² -3x -6x +18 <em>(</em><em>Expand</em><em>)</em>
= x² -9x +18
Area of shaded region
= 6x² -2x -8 -(x² -9x +18)
= 6x² -2x -8 -x² +9x -18
= 5x² +7x -26