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Serga [27]
3 years ago
10

Let P(x) be the statement"x= x2", If the domain consists of the integers, what are these truth values? (a) P(0) (b) P(1) (c) P(2

) (d) P(-1) (e)
Mathematics
1 answer:
jeka57 [31]3 years ago
6 0

Answer: i guess the problem is with P(x) => "x = x^{2}", then P(x) is true if that equality is true, and is false if the equality is false.

so lets see case for case.

a) x = 0, and 0^{2} = 0. So p(0) is true.

b) x = 1 and 1^{2} = 1, so P(1) is true.

c) x = 2, and 2^{2} = 4, and 2 ≠ 4, then P(2) is false.

d) x= -1 and 1^{2} = 1, and 1 ≠ -1, so P(-1) is false.

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What would the answer to this question be? show work please
AURORKA [14]

Answer:

B

Step-by-step explanation:

The volume of a rectangular prism is the length times width times height.

V = LWH

V = (4√3)(3√6)W

V = 12√18 W

V = 36√2 W

If the volume is irrational, then W cannot have a radical that is half of a perfect square, because when multiplied by √2, that would yield a rational volume.  For example, √18 × √2 = √36 = 6.

Therefore, the answer must be B, because 12 is not half of a perfect square.

V = 36√2 (4√12)

V = 144√24

V = 288√6

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4 years ago
If (x) = 3x - 5 and g(x) = x + 3, find (f - g)(x).
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Answer:

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Step-by-step explanation:

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(f - g)(x) = 3x - 5 - ( x+3)

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quotient means divide

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3 0
3 years ago
PLEASE HELP FAST!!!
Rus_ich [418]

\\ \sf\longmapsto 3s-5+2s+25=170

\\ \sf\longmapsto 5s+20=170

\\ \sf\longmapsto 5s=170-20

\\ \sf\longmapsto 5s=150

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