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Serga [27]
3 years ago
10

Let P(x) be the statement"x= x2", If the domain consists of the integers, what are these truth values? (a) P(0) (b) P(1) (c) P(2

) (d) P(-1) (e)
Mathematics
1 answer:
jeka57 [31]3 years ago
6 0

Answer: i guess the problem is with P(x) => "x = x^{2}", then P(x) is true if that equality is true, and is false if the equality is false.

so lets see case for case.

a) x = 0, and 0^{2} = 0. So p(0) is true.

b) x = 1 and 1^{2} = 1, so P(1) is true.

c) x = 2, and 2^{2} = 4, and 2 ≠ 4, then P(2) is false.

d) x= -1 and 1^{2} = 1, and 1 ≠ -1, so P(-1) is false.

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Given that set A has 48 elements and set B has 21 elements, determine each of the following. (a) The maximum possible number of
yKpoI14uk [10]

Answer:  The required answers are

(a) 69,  (b) 21,  (c) 21  and  (d) 0.

Step-by-step explanation:  We are given that the set A has 48 elements and the set B has 21 elements.

(a) To determine the maximum possible number of elements in A ∪ B.

If the sets A and B are disjoint, that is they do not have any common element. Then, A ∩ B = { }   ⇒   n(A ∩ B) = 0.

From set theory, we have

n(A\cup B)=n(A)+n(B)-n(A\cap B)=48+21-0=69.

So, the maximum possible number of elements in  A ∪ B is 69.

(b) To determine the minimum possible number of elements in A ∪ B.

If the set B is a subset of set A, that is all the elements of set B are present in set A. Then,  n(A ∩ B) = 21.

From set theory, we have

n(A\cup B)=n(A)+n(B)-n(A\cap B)=48+21-21=48.

So, the minimum possible number of elements in  A ∪ B is 21.

(c) To determine the maximum possible number of elements in A ∩ B.

If the set B is a subset of set A, that is all the elements of set B are present in set A. Then, n(A ∩ B) = 21.

So, the maximum possible number of elements in  A ∩ B is 21.

(d) To determine the minimum possible number of elements in A ∩ B.

If the sets A and B are disjoint, that is there is no common element in the sets A and B . Then,  n(A ∩ B) = 0.

So, the maximum possible number of elements in  A ∩ B is 0.

Thus, the required answers are

(a) 69,  (b) 21,  (c) 21  and  (d) 0.

6 0
3 years ago
Connecticut families were asked how much they spent weekly on groceries. Using the following data, construct and interpret a 95%
Amanda [17]

Answer:

The 95% confidence interval for the population mean amount spent on groceries by Connecticut families is ($73.20, $280.21).

Step-by-step explanation:

The data for the amount of money spent weekly on groceries is as follows:

S = {210, 23, 350, 112, 27, 175, 275, 50, 95, 450}

<em>n</em> = 10

Compute the sample mean and sample standard deviation:

\bar x =\frac{1}{n}\cdot\sum X=\frac{ 1767 }{ 10 }= 176.7

s= \sqrt{ \frac{ \sum{\left(x_i - \overline{x}\right)^2 }}{n-1} }       = \sqrt{ \frac{ 188448.1 }{ 10 - 1} } \approx 144.702

It is assumed that the data come from a normal distribution.

Since the population standard deviation is not known, use a <em>t</em> confidence interval.

The critical value of <em>t</em> for 95% confidence level and degrees of freedom = n - 1 = 10 - 1 = 9 is:

t_{\alpha/2, (n-1)}=t_{0.05/2, (10-1)}=t_{0.025, 9}=2.262

*Use a <em>t</em>-table.

Compute the 95% confidence interval for the population mean amount spent on groceries by Connecticut families as follows:

CI=\bar x\pm t_{\alpha/2, (n-1)}\cdot\ \frac{s}{\sqrt{n}}

     =176.7\pm 2.262\cdot\ \frac{144.702}{\sqrt{10}}\\\\=176.7\pm 103.5064\\\\=(73.1936, 280.2064)\\\\\approx (73.20, 280.21)

Thus, the 95% confidence interval for the population mean amount spent on groceries by Connecticut families is ($73.20, $280.21).

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