Hello:
let : f(x) = <span>x3 − 6x2 + kx + 10
</span><span>If (x + 2) is a factor of x3 − 6x2 + kx + 10 : f(-2) = 0
(-2)^3-6(-2)² +k(-2)+10=0
-8 -24-2k +10 = 0
-2k =8+24-10
-2k = 22
k = -11</span>
Answer:
(-3,-1)
Step-by-step explanation:
-x+y=2
3x-5y=-4
in the top equation, we can get y by itself on one side of the equation:
-x+y=2
y=x+2
now, since we know that y=x+2, in the bottom equation we can substitute x+2 for y (substitution method) and solve:
3x-5y=-4
3x-5(x+2)=-4
3x-5x-10=-4
-2x-10=-4
-2x=6
x=-3
since we now know that x=-3, we can use it to find y by plugging in -3 for x in the top equation (you can do it in either equation, but doing it in the top equation is easier):
y=x+2
y=-3+2
y=-1
answer: (-3, -1)
Answer:
See below.
Step-by-step explanation:
The graph of the quadratic equation is a parabola or u shaped graph. It has a vertex at (-1,-3) since h=-1 and k=-3 in the vertex form. It is also facing down since the leading coefficient is negative.
