Question

XB is the angle bisector of ZAXC. MZAXB23А.BVхC с

Answer 1

To obtain x, we can sum the angles < AQB and < BQC

=> 5X + 8X - 24

=> 13X -24

we are also told that that the sum of their angles is 80

13X - 24 = 80

13 X = 24 + 80

13X = 104

Divide both sides by 13

x = 104/13

x = 8