The electric field strength at any point from a charged particle is given by E = kq/r^2 and we can use this to calculate the field strength of the two fields individually at the midpoint.
The field strength at midway (r = 0.171/2 = 0.0885 m) for particle 1 is E = (8.99x10^9)(-1* 10^-7)/(0.0885)^2 = -7.041 N/C and the field strength at midway for particle 2 is E = (8.99x10^9)(5.98* 10^-7)/(0.0935)^2 = <span>-7.041 N/C
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Note the sign of the field for particle 1 is negative so this is attractive for a test charge whereas for particle 2 it is positive therefore their equal magnitudes will add to give the magnitude of the net field, 2*<span>7.041 N/C </span>= 14.082 N/C
Hat do you know someone called English
Answer:
The answers are...:
The common ratio is -3
the sequence of the function is 2,-6, 18, -54, 162
and
the sequence of the function model is geometric
I hope this helps ^^"
Step-by-step explanation:
the common ratio is just from the -3 itself
the sequence model is just plugging n for every term so
a(1) would equal to 2, a(2)=-6 , a(3) would equal to -18, etc
and the geometric is bc it has the exponential that has (n-1), thus it is a geometric sequence
Y=12
The angles are 45°, 114°,105°,96° & 84°
