All categories

3 years ago

Help me on this please

Mathematics

1 answer:

djyliett [7]3 years ago

6 0

${x}^{2} = {17}^{2} - {11}^{2} \\ {x}^{2} = 289 - 121 = 168 \\ x = \sqrt{168 } = 12.96$

You might be interested in

What the min preicatorin x

Sladkaya [172]

Answer:

idk refrace your question

Step-by-step explanation:

3 0

3 years ago

The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e

marusya05 [52]

Answer:

The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:

$\hat p =\frac{955-812}{955}= 0.150$

$0.150 - 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.131$

$0.150 + 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.169$

And the 90% confidence interval would be given (0.131;0.169).

Step-by-step explanation:

We have the following info given:

$n= 955$ represent the sampel size slected

$x = 812$ number of students who read above the eighth grade level

The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:

$\hat p =\frac{955-812}{955}= 0.150$

The confidence interval for the proportion would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 90% confidence interval the significance is $\alpha=1-0.9=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the normal standard distribution and we got.

$z_{\alpha/2}=1.64$

And replacing into the confidence interval formula we got:

$0.150 - 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.131$

$0.150 + 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.169$

And the 90% confidence interval would be given (0.131;0.169).

8 0

3 years ago

It has been reported that 48% of teenagers play video games on their phones. A random sample of 60 teenages is drawn. Find the p

Ivanshal [37]

Answer:

skakaaja

Step-by-step explanation:

aamnanananan

3 0

3 years ago

34.7985347985 rounded to the nearest tenth

Nina [5.8K]

The answer would be 34.8 I’m pretty sure

7 0

2 years ago

Read 2 more answers

A water container has 19.5 litres of water in it. A cup holds 210 ml of water. At most 92 cups can be filled completely from the

coldgirl [10]

Step-by-step explanation:

Given

A container has 19.5 liters of water

A cup can hold 210 ml of water

1 L is equivalent to 1000 ml

So, 19.5 L is equivalent to $19.5\times 1000=19,500\ ml$

So, the number of requires to hold this much water

$\Rightarrow n=\dfrac{19,500}{210}\\\\\Rightarrow n=92.85\ \text{cups}$

92.85 implies 92 full cups and 1 cup which is partially filled. Hence, almost 92 cups can be filled completely.

5 0

2 years ago