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Veronika [31]
3 years ago
14

I need to solve the absolute value for |4q+9|=|2q-1| please help!!!

Mathematics
1 answer:
liraira [26]3 years ago
6 0

Answer:

q \in \{\frac{-4}{3},-5\}

Step-by-step explanation:

If this has at least one solution then it will come from either 4q+9=2q-1 or from 4q+9=-(2q-1).

Let' solve the first:

4q+9=2q-1

Subtract 2q on both sides:

2q+9=-1

Subtract 9 on both sides:

2q=-10

Divide both sides by 2:

q=-5

Let's check it into the original equation:

|4(-5)+9|=|2(-5)-1|

|-20+9|=|-10-1|

|-11|=|-11|

11=11

So q=-5 checks out as a solution.

Let's solve the other equation:

4q+9=-(2q-1)

Distribute:

4q+9=-2q+1

Add 2q on both sides:

6q+9=1

Subtract 9 on both sides:

6q=-8

Divide both sides by 6:

q=-8/6

Reduce:

q=-4/3

Let's check it into the original equation:

|4(-4/3)+9|=|2(-4/3)-1|

|-16/3+9|=|-8/3-1|

|11/3|=|-11/3|

11/3=11/3

So q=-4/3 also checks out since both sides are the same when plugging in q=-4/3.

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All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be
Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

A = a + (A \cap B)

In which a is the probability that a student is proficient in reading but not mathematics and A \cap B is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

B = b + (A \cap B)

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

(A \cup B) + C = 1

In which

(A \cup B) = a + b + (A \cap B)

65% were found to be proficient in both reading and mathematics.

This means that A \cap B = 0.65

78% were found to be proficient in mathematics

This means that B = 0.78

B = b + (A \cap B)

0.78 = b + 0.65

b = 0.13

85% of the students were found to be proficient in reading

This means that A = 0.85

A = a + (A \cap B)

0.85 = a + 0.65

a = 0.20

Proficient in at least one:

(A \cup B) = a + b + (A \cap B) = 0.20 + 0.13 + 0.65 = 0.98

What is the probability that the student is proficient in neither reading nor mathematics?

(A \cup B) + C = 1

C = 1 - (A \cup B) = 1 - 0.98 = 0.02

There is a 2% probability that the student is proficient in neither reading nor mathematics.

6 0
3 years ago
X=18+9/2y help <br> Me please
Nana76 [90]

Answer:

x = 18 + 9y/2

x-18 = 9y/2

(x-18)x2=9y

2(x-18)=9y

2(x-18) / 9 = y

y= 2(x-18)/9

Step-by-step explanation:

<em>Simplify 9/2y to 9y/2</em>

<em>Then Subtract 18 from both sides</em>

<em>Now Multiply both sides by 2</em>

<em>Then Regroup the terms</em>

<em>now divide both sides by 9</em>

<em>Then you will Switch sides</em>

4 0
4 years ago
-4x - 6x = -20 =?<br><br> -3(2x - 3) = 33 = ?<br><br> 4x + 3x + 2x = 180 = ?
postnew [5]

Answer:

-4x-6x=-20=

x=2

-3(2x-3)=33=

x=-4

4x+3x+2x=180

x=20

Step-by-step explanation:

-4x-6x=-20                                

-4+(-6)=-10x

-10x=20 (divide both by 10)

x=-2 (divide by -1 to get positive)

x=2

-3(2x-3)=33

-6x+9=33

     -9 .  -9

-6x=24 (divide both by -6)

x=-4 (divide by -1 to make positive)

4x+3x+2x=180

(combine like terms)

9x=180 (divide both sides by 9)

x=20

5 0
3 years ago
Adele ate lunch at a restaurant. The bill came to $90. If she left a 15% tip, how much was the
o-na [289]

Answer:

$13.50

Step-by-step explanation:

The total is $103.50.

4 0
3 years ago
Read 2 more answers
Help! In parallelogram LMNO below, find the length of MO
pashok25 [27]

Answer:

Step-by-step explanation:

The diagonals of a parallelogram bisect each other.

5y - 8 = 3y + 1              Add 8 to both sides

5y = 3y + 1 + 8             Subtract 3y from both sides

5y - 3y = 9                   Combine

2y = 9                          Divide by 2

2y/2 =9/2  

y = 4. 5

5y - 8 =

5(4.5) - 8 =

22.5 - 8 =

14.5

That represents 1/2 of MO

MO = 2 * 14.5

MO = 29

5 0
3 years ago
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