Answer:
<em><u>1 and 5</u></em>
Step-by-step explanation:
The squares have a side length of 10 and 1 square side is the radius of the half-circles. Since there are two half-circles, find the circumference for one full circle:
![C=2\pi r](https://tex.z-dn.net/?f=C%3D2%5Cpi%20r)
Insert the radius:
![r=10\\C=2\pi *10](https://tex.z-dn.net/?f=r%3D10%5C%5CC%3D2%5Cpi%20%2A10)
Simplify pi:
![C=2*3.14*10](https://tex.z-dn.net/?f=C%3D2%2A3.14%2A10)
Simplify multiplication:
![C=6.28*10\\C=62.8](https://tex.z-dn.net/?f=C%3D6.28%2A10%5C%5CC%3D62.8)
The circumference of the circles is 62.8. Now find the perimeter of the exposed squares with side length 10. There are 4 exposed sides, which equals one square. Find the perimeter:
![P=10+10+10+10\\P=10+10+20\\P=10+30\\P=40](https://tex.z-dn.net/?f=P%3D10%2B10%2B10%2B10%5C%5CP%3D10%2B10%2B20%5C%5CP%3D10%2B30%5C%5CP%3D40)
Add the perimeter of the circle and the square together:
![P=62.8+40=102.8](https://tex.z-dn.net/?f=P%3D62.8%2B40%3D102.8)
Now see which of the options gives you the perimeter:
1.
****
2. ![unavailable](https://tex.z-dn.net/?f=unavailable)
3. ![120+20\pi =182.8](https://tex.z-dn.net/?f=120%2B20%5Cpi%20%3D182.8)
4. ![300+100\pi =614.2](https://tex.z-dn.net/?f=300%2B100%5Cpi%20%3D614.2)
5.
****
Finito.
Changing a fraction to its decimal form can be done by long division method. Dividing the denominator by its numerator will change the fraction into decimal form. Alternatively, you can use a calculator to do that for you. Below are the fractions with their decimal forms listed:
1.) 2/5 = 0.4 (D)
2.) 7/20 = 0.35 (A)
3.) 3/25 = 0.12 (C)
4.) 7/10 = 0.7 (B)
No because the exponent on 6^3 is 216 and if you use (4•6)^3 then you’ll have to multiply the quotations and then Square it to the third
By ASA postulate it can be say that the triangle ABC and triangle MRQ are congruent
<h3>What is Angle Sum Property?</h3>
The sum of all three angles(interior) of a triangle is 180 degrees, and the exterior angle of a triangle measures the same as the sum of its two opposite interior angles.
Using Angle Sum Property, in ΔMRQ
<M + <R + <Q= 180
<M + 42 + 85 = 180
<M = 180 -42
<M= 53°
Now, In ΔMRQ and ΔABC
<A= <R ,
<B = <M
AB = MR
Hence, By ASA criteria ΔMRQ ≅ ΔABC
Learn more about this concept here:
brainly.com/question/3486366
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