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KATRIN_1 [288]
3 years ago
7

Can someone tell me if this adjacent , vertical or linear

Mathematics
1 answer:
babymother [125]3 years ago
5 0

Answer:

adjacent

you can search it up it's one of the first pictures

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Plesseeeeeeee hellllllllllppp
Ugo [173]
The answer would be (F) 14

8 0
3 years ago
An advertisement for a popular weight-loss clinic suggests that participants in its new diet program lose, on average, more than
Sedbober [7]

Testing the hypothesis, it is found that:

a)

The null hypothesis is: H_0: \mu \leq 10

The alternative hypothesis is: H_1: \mu > 10

b)

The critical value is: t_c = 1.74

The decision rule is:

  • If t < 1.74, we <u>do not reject</u> the null hypothesis.
  • If t > 1.74, we <u>reject</u> the null hypothesis.

c)

Since t = 1.41 < 1.74, we <u>do not reject the null hypothesis</u>, that is, it cannot be concluded that the mean weight loss is of more than 10 pounds.

Item a:

At the null hypothesis, it is tested if the mean loss is of <u>at most 10 pounds</u>, that is:

H_0: \mu \leq 10

At the alternative hypothesis, it is tested if the mean loss is of <u>more than 10 pounds</u>, that is:

H_1: \mu > 10

Item b:

We are having a right-tailed test, as we are testing if the mean is more than a value, with a <u>significance level of 0.05</u> and 18 - 1 = <u>17 df.</u>

Hence, using a calculator for the t-distribution, the critical value is: t_c = 1.74.

Hence, the decision rule is:

  • If t < 1.74, we <u>do not reject</u> the null hypothesis.
  • If t > 1.74, we <u>reject</u> the null hypothesis.

Item c:

We have the <u>standard deviation for the sample</u>, hence the t-distribution is used. The test statistic is given by:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

The parameters are:

  • \overline{x} is the sample mean.
  • \mu is the value tested at the null hypothesis.
  • s is the standard deviation of the sample.
  • n is the sample size.

For this problem, we have that:

\overline{x} = 10.8, \mu = 10, s = 2.4, n = 18

Thus, the value of the test statistic is:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{10.8 - 10}{\frac{2.4}{\sqrt{18}}}

t = 1.41

Since t = 1.41 < 1.74, we <u>do not reject the null hypothesis</u>, that is, it cannot be concluded that the mean weight loss is of more than 10 pounds.

A similar problem is given at brainly.com/question/25147864

3 0
3 years ago
In the soccer games so far this season, Letty has had 15 goals in 20 attempts at a goal. What is the probability, expressed as a
Inga [223]
20 is 1/5 of 100 so do 20x5=100 and 15x5=75


So there is a 75% chance she will make the goal
6 0
3 years ago
Read 2 more answers
What is 1 and 1/4% of 200?
arsen [322]
5/4 • 200/1, 1000/4
which is 250

250 is 1 1/4 of 200
4 0
3 years ago
100m In 9 3/5 seconds
Nostrana [21]

Answer:

Speed = 10.42 m/secs

Step-by-step explanation:

We have been given with:-

Distance = 100m

Time taken = 9\frac{3}{5} secs

1) First, we need to convert the mixed number 9\frac{3}{5} to an improper fraction.

<u>Method to convert a mixed number to an improper fraction</u>

<u>a\frac{b}{c} = \frac{c*a+b}{c}</u>

Applying the above formula, we get

9\frac{3}{5} = \frac{5*9+3}{5}

= \frac{45+3}{5}

= \frac{48}{5}

2) Now we need to convert \frac{48}{5} into a decimal by dividing 48 by 5.

We get time taken as 9.6 secs

3) We need to find the speed using the below formula:-

Speed = \frac{Distance}{Time taken}

Plugging the values of Distance and Time taken into the formula, we get

Speed = \frac{100}{9.6}

= 10.416 m/secs

4) Upon rounding it to the nearest hundredth, we get

Speed = 10.42 m/secs

4 0
3 years ago
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