Answer:
Option B. minimum is correct for the first blank
Option C. 6 is correct for second blank.
Step-by-step explanation:
In order to find the maxima or minima of a function, we have to take the first derivative and then put it equal to zero to find the critical values.
Given function is:

Taking first derivative

Now the first derivative has to be put equal to zero to find the critical value

The function has only one critical value which is 5.
Taking 2nd derivative


As the value of 2nd derivative is positive for the critical value 5, this means that the function has a minimum value at x = 5
The value can be found out by putting x=5 in the function

Hence,
<u>The function y = x 2 - 10x + 31 has a minimum value of 6</u>
Hence,
Option B. minimum is correct for the first blank
Option C. 6 is correct for second blank.
Answer:
the secound ansewr
Step-by-step explanation:ik
I think you need to add a picture?
The answer is 85%.
If you're solving without a calculator, you can simply multiply the numerator and denominator so that the denominator is equal to 100. So, for this fraction, you would multiply both the top and the bottom by 5.
17/20
17(5) / 20(5)
85 / 100
85%
Answer:
to be honest idek
Step-by-step explanation: