How can a regular hexagon be folded to show that it has reflectional Symmetry?
2 answers:
Answer:
the answer is to fold the hexagon along a line that bisects two vertex angles.
Step-by-step explanation:
pls mark me as a brainllest
Answer:
fold the hexagon along a line that bisects two vertex angles:)
Step-by-step explanation:
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The answer is 22.8
Cos 64 = adj./hypotenuse
Cos64=10/x
X(cos64)=10
X= 10/cos64
= 22.8
Answer:
10%
Step-by-step explanation:
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